The wavelength of He-Ne laser light traveling through air is 633 nm. The wavelength of He-Ne laser light traveling through the mystery medium is 329 nm.

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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
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Chapter27: Wave Optics
Section: Chapter Questions
Problem 60PE: (a) What is the minimum angular spread of a 633-nm wavelength He-Ne laser beam that is originally...
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2. What is the mystery medium?
The wavelength of He-Ne laser light traveling through air is 633 nm.
The wavelength of He-Ne laser light traveling through the mystery
medium is 329 nm.
a. What is the index of refraction of the medium?
b. Based on the table below, what is the most likely medium?
Materials at 20°C for light with a vacuum wavelength of 589 nm.
Material
diamond
fluorite
Material
benzene
1.501
carbon disulfide 1.628
carbon
tetrachloride
ethanol
glycerine
water (fresh)
2.419
1.434
1.461
glass
(crown)
glass (flint) 1.66
1.361
1.473 ice (0°C) 1.309
1.333 polystyrene 1.49
1.52
Material
plexiglas
quartz
(crystalline)
151
1.544
quartz (fused) 1.458
sodium chloride 1.544
zircon
1.923
air
1.00029
We can find out what the
mystery medium is by
measuring the wavelength of
light in the medium and
calculating its index of
refraction.
n =
2<
Skills: Relate
change of
wavelength of light
in a medium
(lambda) to the
index of refraction
(n) of the material.
Transcribed Image Text:2. What is the mystery medium? The wavelength of He-Ne laser light traveling through air is 633 nm. The wavelength of He-Ne laser light traveling through the mystery medium is 329 nm. a. What is the index of refraction of the medium? b. Based on the table below, what is the most likely medium? Materials at 20°C for light with a vacuum wavelength of 589 nm. Material diamond fluorite Material benzene 1.501 carbon disulfide 1.628 carbon tetrachloride ethanol glycerine water (fresh) 2.419 1.434 1.461 glass (crown) glass (flint) 1.66 1.361 1.473 ice (0°C) 1.309 1.333 polystyrene 1.49 1.52 Material plexiglas quartz (crystalline) 151 1.544 quartz (fused) 1.458 sodium chloride 1.544 zircon 1.923 air 1.00029 We can find out what the mystery medium is by measuring the wavelength of light in the medium and calculating its index of refraction. n = 2< Skills: Relate change of wavelength of light in a medium (lambda) to the index of refraction (n) of the material.
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