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There are 1.65 m in 1 Altuve, knowing this: 1 Altuve^3 =___ m^3
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- A soft drink contains an unknown mass of citric acid, C3H5O(COOH)3. It requires 6.42 mL of 9.580 × 10−2-M NaOH to neutralize the citric acid in 10.0 mL of the soft drink. C3H5O(COOH)3(aq) + 3 NaOH(aq) → Na3C3H5O(COO)3(aq) + 3 H2O(ℓ) Determine which step in these calculations for the mass of citric acid in 1 mL soft drink is incorrect? Why? n (NaOH) = (6.42 mL)(1L/1000 mL)(9.580 × 10−2 mol/L) n (citric acid) = (6.15 × 10−4 mol NaOH) × (3 mol citric acid/1 mol NaOH) m (citric acid in sample) = (1.85 × 10−3 mol citric acid) × (192.12 g/mol citric acid) m (citric acid in 1 mL soft drink) = (0.354 g citric acid)/(10 mL soft drink) Determine the correct result.How many grams of oxalic acid, H2C2O4, are required to prepare 750. mL of a 0.250 M oxalic acid solution? Report your result in decimal notation and to the proper number of significant figures.Calculate the volume of NaOH solution the student will need to add to reach the final equivalence point. Round your answer to 3significant digits.
- One gram of saltpeter (KNO3) is dissolved in two hundred milliliters water. Assume the density of salt peter powder to be 2.11 g/cm3. Calculate the mass percent of saltpeter in the solution. a. 0.398 b. 99.602 c. 0.5 d. 99.6 How many parts per million of saltpeter is there in the solution?* a. 5000 b. 4988.2 c. 5053.3 d. 4947.8In the laboratory, a student dilutes 26.7 mL of a 7.32 M hydrochloric acid solution to a total volume of 125.0 mL. What is the concentration of the diluted solution?A Chemistry student has to prepare 155 mL of 0.100 M KI in water. She finds a bottle that states it is 10.00% KI in water and has a density of 1.07 g/mL. She takes 1.55 mL of the 10.00 % solution and dilutes it to a final volume of 155 mL. Support your answers with correct calculations. a) What is the concentration of the solution he prepared? b) If she did not prepare the solution correctly, what should she have done? c) Suppose what she needed to prepare was a solution that was 155 mL of 0.100% in KI. Would taking 1.55 mL of the 10.00% KI solution and diluting to 155 mL have worked? Why not?
- Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 120.00 mL. Given that the concentration of the most dilute solution is 3.52 × 10−6 M, determine the concentration of the original HBr stock solution.A chemistry student weighs out 0.0909g of hypochlorous acid HClO into a 250.mL volumetric flask and dilutes to the mark with distilled water. He plans to titrate the acid with 0.1400M NaOH solution. Calculate the volume of NaOH solution the student will need to add to reach the equivalence point. Be sure your answer has the correct number of significant digits.A solution is prepared by dissolving 59.3 g of KI in enough water to make 350mL of solution. Calcuate the mass % of KBr in the solution if the density is 1.12 g/mL. a. 15.1% b. 16.9 % c. 9.31% d. 13.1% e. 14.5%
- Five standard solutions of HBr are prepared by serial dilution in which, at each stage, 10.00 mL are diluted to 130.00 mL. Given that the concentration of the most dilute solution is 3.42 ×10−6 M, determine the concentration of the original HBr stock solution.In the laboratory, a student dilutes 12.8 mL of a 9.35 M perchloric acid solution to a total volume of 250.0 mL. What is the concentration of the diluted solution?The solution in the book said the total volume was 25 + 30, and I don't understand why. Is this an error in their solution?
