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There are two benzylic bromides that give (E)-3,5-dimethyl-2-phenyl-2-hexene on E2 elimination. Draw them.
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- Consider 3-iodo-2,3-dimethylpentane and 3-iodo-2methylpentane. a. which reacts faster in an Sn2 reaction? Explain. b. which reacts faster in an E2 reaction? Explain.Which base gives the fastest E1 reaction 2-chloro-2-methylpentane? Select one: a. iso-butoxide b. none of these c. t-Butoxide d. sec-butoxideRank the alkyl halides in each group in order of increasing reactivity in an E2 reaction.
- What is the major E2 elimination product formed from each alkyl halide?The Hofmann product is favored by the E2 mechanism when 2-bromo-3-methylbutane is added: A. MeOH B. MeO:- in MeOH C. Nal in acetona D. (CH 3)3 CO:- in (CH 3),COHWhich of the following bases gives the highest Zaitsev product in an E2 reaction with 2-bromo-2,3-dimethylbutane?
- Explain the effect of the structure of the alkyl halide on elimination via E1 or E2.Given that an E2 reaction proceeds with anti periplanar stereochemistry, draw the products of each elimination. The alkyl halides in (a) and (b) are diastereomers of each other. How are the products of these two reactions related? Recall from Section 3.2A that C6H5 −is a phenyl group, a benzene ring bonded to another group.Given that an E2 reaction proceeds with anti periplanar stereochemistry, draw the products of each elimination. The alkyl halides in (a) and (b) are diastereomers of each other. How are the products of these two reactions related? Recall from Section 3.2A that C6H5– is a phenyl group, a benzene ring bonded to another group.