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Thermodynamics: Work and Heat Show solution step by step. Please answer correctly. 1. Carbon dioxide is compressed frictionlessly in a steady flow process in such a manner that pv0.5 constant from 100 to 500 kPa. The initial specific volume is 0.56 m³/kg. Calculate the work per kilogram of gas. Assume Ape=AKe=0. Answer: -44.8 kJ/k 2. In a quasi – equilibrium process in a closed system, a gas expands from a volume of 0.15 m³ and a pressure of 120 kPa to a volume of 0.25 m³ in such a manner that p(V+0.03) = constant, where V is in m3. Calculate the work. Answer: 9.543 kJ

Thermodynamics: Work and Heat Show solution step by step. Please answer correctly. 1. Carbon dioxide is compressed frictionlessly in a steady flow process in such a manner that pv0.5 constant from 100 to 500 kPa. The initial specific volume is 0.56 m³/kg. Calculate the work per kilogram of gas. Assume Ape=AKe=0. Answer: -44.8 kJ/k 2. In a quasi – equilibrium process in a closed system, a gas expands from a volume of 0.15 m³ and a pressure of 120 kPa to a volume of 0.25 m³ in such a manner that p(V+0.03) = constant, where V is in m3. Calculate the work. Answer: 9.543 kJ

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Thermodynamics: Work and Heat Show solution step by step. Please answer correctly. 1. Carbon dioxide is compressed frictionlessly in a steady flow process in such a manner that pv0.5 constant from 100 to 500 kPa. The initial specific volume is 0.56 m³/kg. Calculate the work per kilogram of gas. Assume Ape=AKe=0. = Answer: -44.8 kJ/k 2. In a quasi – equilibrium process in a closed system, a gas expands from a volume of 0.15 m3 and a pressure of 120 kPa to a volume of 0.25 m3 in such a manner that p(V+0.03) = constant, where V is in m³. Calculate the work. Answer: 9.543 kJ
Transcribed Image Text:Thermodynamics: Work and Heat Show solution step by step. Please answer correctly. 1. Carbon dioxide is compressed frictionlessly in a steady flow process in such a manner that pv0.5 constant from 100 to 500 kPa. The initial specific volume is 0.56 m³/kg. Calculate the work per kilogram of gas. Assume Ape=AKe=0. = Answer: -44.8 kJ/k 2. In a quasi – equilibrium process in a closed system, a gas expands from a volume of 0.15 m3 and a pressure of 120 kPa to a volume of 0.25 m3 in such a manner that p(V+0.03) = constant, where V is in m³. Calculate the work. Answer: 9.543 kJ
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