They are asked if they use a laptop in dass to take notes Based on What is the approximate 95N confidence interval for the true proportion of students using a laptop to take notes? (use the 68-95-99.7 nule) O (0.4757, 0.8643) 2 (0.5757. 0.7643) (0.5457, 0.7943)

Q: . Suppose a 90% confidence interval is stated as (0.3011, 0.4189). What is the margin of error?…

A: The confidence interval formula of population proportion is (p̂ ± E), where p̂ is the sample…

Q: In a survey of 1741 US adults, 697 said they think genetically modified food is safe. A 95%…

A: Given that  Sample size n =1741 Favorable cases x =697 Sample proportion p^=x/n  =697/1741 =0.4

Q: 2. Out of a sample of 760 people, 367 own their homes.. Construct a 95% confidence interval for the…

A:

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A: Obtain the upper limit of the 95% confidence interval for the estimate of true proportion. The upper…

Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: A student was asked to find a 90% confidence interval for the proportion of students who take notes…

A:

Q: The average percentage of cities in the US that have snow on Christmas Day is 35%. A recent sample…

A: From the provided information, The average percentage of cities in the US that have snow on…

Q: he UW school of medicine, 750 of 1000 adult Seattle residents said they did not believe they could…

A: The sample proportion is computed as follows: The corresponding confidence interval is computed as…

Q: A student was asked to find a 99% confidence interval for the proportion of students who take notes…

A: Given n=89. 99% Ci for population proportion p  0.12<p<0.34

Q: What is the tc for a 0.99 confidence level when the sample is19? If no preliminary study is made to…

A: Given information: a) Confidence level = 0.99 Sample size = 19 D.F = n - 1 D.F = 18

Q: In a recent poll, 250 people were asked if they liked dogs, and 8% said they did. Find the Margin of…

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Q: In a recent poll, 120 people were asked if they liked dogs, and 41% said they did. Find the Margin…

A: From the given information, Sample size = 120 Sample proportion = 0.41   The objective is to find…

Q: An airline observes a random sample of its flights on a particular route. The 95%confidence interval…

A: Given that the 95% confidence interval for the mean time for all flights on this route is (47.0,…

Q: The workers at a certain company took a random sample of 800 manhole covers and found that 40 of…

A:

Q: A student was asked to find a 90% confidence interval for the proportion of students who take notes…

A: The 90% confidence interval for proportion of students who take notes is 0.11<p < 0.24.

Q: Construct a 99% confidence interval for the true average number of visitors per day to a fun park,…

A: Obtain the 99% confidence interval for the true average number of visitors per day to a fun work.…

Q: A recent survey showed that among 650 randomly selected subjects who completed 4 years of college,…

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Q: A newsgroup is interested in constructing a 90% confidence interval for the proportion of all…

A: A newsgroup is interested in constructing a 90% confidence interval for the proportion of all…

Q: A survey of 1000 randomly selected smartphone users found that 86.1% of them used an Android…

A: For the given data Find EBP = ?

Q: Find the following. Enter your answer rounded to at least two decimals. for the 86% confidence…

A: We have given 86% confidence level and we have to find right tailed Z value for it.

Q: A study of 420,095 Danish cell phone users found that 0.0321% of them developed cancer of the brain…

A: From the provided information, Sample size (n) = 420095 Sample proportion (p̂) = 0.0321% Confidence…

Q: (a) Find a 95% confidence interval for p1 - P2. (Use 3 decimal places.)

A: (a) A random sample of 336 married couples found that 292 had two or more personality preferences in…

Q: A chain of coffee shops wishes to determine how many of their customers prefer Mocha Latte. A random…

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Q: In a survey funded by the UW school of medicine, 750 of 1000 adult Seattle residents said they did…

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Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

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Q: Use the given confidence interval to find (0.756,0.780) E3D (Type an integer integer or a decimal.)

A: Given: confidence interval ( 0.756 , 0.78 ) Need to find sample mean(x̄) and margin of error(ME) .

Q: According to a report, 65% of parents of teens aged 13 to 17 said that they had checked which web…

A: Given: Sample proportion=p=0.65. Sample size=n=1020.

Q: 8. A dietitian read a survey that states that at least 60% of adults eat eggs for breakfast at least…

A: Given, population proportion p=0.60, n=100, p^=0.54, level of significance ɑ=0.10

Q: A student was asked to find a 90% confidence interval for the proportion of students who take notes…

A: Given,sample size(n)=81confidence interval(C.I)=0.15<p<0.31α=1-0.90=0.1α2=0.05Z0.05=1.645…

Q: In a recent poll, 490 people were asked if they liked dogs, and 51% said they did. Find the Margin…

A: Given data,n=490p=51%=0.51z-value at 99% confidence is Zc=2.576E=?

Q: In a recent poll, 250 people were asked if they liked dogs, and 17% said they did. Find the Margin…

A: Step-by-step procedure to obtain the value of  using STATKEY:Choose Normal under Theoretical…

Q: A student was asked to find a 95% confidence interval for the proportion of students who take notes…

A: Given info: A student was asked to find a 95% confidence interval for the proportion of students who…

Q: A student was asked to find a 99% confidence interval for the proportion of students who take notes…

A: Given information- Sample size, n = 88 Confidence level, c = 99% We have given the confidence…

Q: A smart phone manufacturer is interested in constructing a 90% confidence interval for the…

A: a) The sample size n= 1595.for The sample proportion is 90/1595=0.0564. The absolute value of Zα/2…

Q: A study of 1907 traffic fatalities found that 725 were alcohol related. Suppose you want your 99%…

A: Given information Total number of traffic fatalities(n) = 1907 Number of fatalities, alcohol related…

Q: A newsgroup is interested in constructing a 99% confidence interval for the proportion of all…

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Q: A marketing consultant wants to estimate the proportion of all shoppers at a certain mall who make…

A: n= 132x = 104P^ = xn = 104132 = 0.7879

Q: Find a 96% confidence interval for Hd. Let Ha =H1 - H2, where u, is the mean solar energy generated…

A: From the provided information, Sample size (n) = 5 Confidence level = 96%

Q: In a recent poll, 230 people were asked if they liked dogs, and 72% said they did. Find the Margin…

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Q: In a sample of 41 men, 25 said that they had less leisure time today than they had 10 years ago. In…

A: From the provided information,

Q: How large a sample is needed if we want to believe 98% that the proportion of the sample found lies…

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Q: A study of 420,095 Danish cell phone users found that 0.0321% of them developed cancer of the brain…

A: Obtain the 90% confidence interval estimate of the percentage of cell phone users who develop cancer…

Q: A student was asked to find a 90% confidence interval for widget width using data from a random…

A: It is given here that the 90% confidence interval for widget width is: 13.5 < μ < 23.1

Q: According to a report published by the Pew Research Center in February 2010, 61% of Millennials…

A: Population proportion is used in hypothesis testing and confidence interval.

Q: A New York Times article reported that a survey conducted in 2014 included  ​36,000 adults, with…

A: Givenp^=0.371confidence level(c)=90%Margin of error(E)-0.01α=1-0.90=0.10α2=0.05zα2=z0.05=1.6449…

Q: What proportion of people living in Quebec believes in Quebec sovereignty? A random sample of n =…

A: From the provided information, Sample size (n) = 375 And the number of people who believe Quebec…

Q: In a recent poll, 490 people were asked if they liked dogs, and 90% said they did. Find the Margin…

A: Given, n=490p∧=90%=0.90 Confidence Interval=(1-α)·100%=99%                         i.e.,  α=0.01

Q: Out of a sample of 760 people, 367 own their homes. Construct a 95% confidence interval for the…

A: