Answer correctly and read the questions corretly, this is all one quesiton if done correclty and organized I will write a very nice review about you! This is atest. Use the Distributions tool to find the critical score(s) for the level of significance a = 0.01.The critical score(s) (the value(s) for t that separate(s) the tail(s) from the main body of the distribution, forming the critical region) is/areTo calculate the test statistic, you first need to calculate the estimated standard error under the assumption that the null hypothesis is true. Theestimated standard error isThe test statistic is t =Use the tool to evaluate the null hypothesis; using t-tables without exact degrees of freedom may not lead to an answer with enoughprecision. (Note: You can place the purple line on your t statistic to tell whether it lies within or outside the critical region. It's possible that thisline may not rest exactly on the t statistic, but you will be able to tell whether it lies within or outside the critical region.) The tstatisticin the critical region for a two-tailed hypothesis test. Therefore, the null hypothesis isstudentconclude that journaling affects grief.The graduateThe graduate student repeats his study with another random sample of the same size. This time, instead of the treatment being journaling abouttheir emotions, the treatment is attending a support group for widows and widowers. Suppose the results are very similar. After attending asupport group for widows and widowers, the mean score was still 0.4 lower, but this time the standard deviation of the difference was 1.2 (vs. theoriginal standard deviation of 1.9). This meanshas the more consistent treatmenteffect.for theThis difference in the standard deviation also means that a 95% confidence interval of the mean difference would beoriginal study, when the treatment was journaling about their emotions, than the 95% confidence interval of the mean difference for the secondstudy, when the treatment was attending a support group for widows and widowers.Finally, this difference in the standard deviation means that when the graduate student conducts a hypothesis test testing whether the meandifference is zero for the second study, he will be likely to reject the null hypothesis than he was for the hypothesis test you completedpreviously for the original study. A graduate student is interested in whether journaling can affect grief and healing. For his study, he selects a random sample of 64 adults whohave been widowed within the past 10 to 14 months. The subjects complete a battery of psychological questionnaires before and after spendingtwo months journaling about their emotions.Before the two months of journaling, the mean score on the impact of event scale-avoidance subscale, which measures how much individualsconsciously avoid thoughts and feelings associated with the loss of their spouses, was 15.4. After the two months of journaling, the mean scorewas 15.0. The mean of the differences between each person's pre- and post- scores was 0.4, with a standard deviation of the differences equalto 1.9.The graduate student has no presupposed assumptions about whether journaling can affect grief and healing, so he formulates the null andalternative hypotheses as:Ho: PD = 0H₁: PD = 0He uses a repeated-measures t test. Because the sample size is large, if the null hypothesis is true as an equality, the test statistic follows at-distribution with n - 1 = 64 - 1 = 63 degrees of freedom.

Question

Accepted Answer

Given that:
Sample size, n=64
Mean of the differences, d¯=0.4
Standard deviation of differences,…