THIS? Read Section Part E ges 803 - 817); Watch KCV 18. 4B, IWE Calculate the pH at one-half of the equivalence point. L sample of 0.165 M propanoic acid ( 3 x 10 5) is titrated with 0.300 Express your answer using two decimal places. pH = Submit Request Answer Part F Calculate the pH at 20 mL of added base.

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter14: Principles Of Neutralization Titrations
Section: Chapter Questions
Problem 14.38QAP
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MISSED THIS? Read Section
Part D
18.4 (Pages 803 -817); Watch KCV 18.4B, IWE
18.7.
Calculate the pH at the equivalence point.
A 30.0-mL sample of 0.165 M propanoic acid (
K = 1.3 x 10-) is titrated with 0.300
М кОН.
Express your answer using two decimal places.
> View Available Hint(s)
pH =
Transcribed Image Text:MISSED THIS? Read Section Part D 18.4 (Pages 803 -817); Watch KCV 18.4B, IWE 18.7. Calculate the pH at the equivalence point. A 30.0-mL sample of 0.165 M propanoic acid ( K = 1.3 x 10-) is titrated with 0.300 М кОН. Express your answer using two decimal places. > View Available Hint(s) pH =
<Chapter 18 Homework
Item 20
MISSED THIS? Read Section
Part E
18.4 (Pages 803 -817); Watch KCV 18.4B, IWE
18.7.
Calculate the pH at one-half of the equivalence point.
A 30.0-mL sample of 0.165 M propanoic acid (
K. = 1.3 x 10-5) is titrated with 0.300
М КОН.
Express your answer using two decimal places.
pH
Submit
Request Answer
Part F
Calculate the pH at 20 mL of added base.
Transcribed Image Text:<Chapter 18 Homework Item 20 MISSED THIS? Read Section Part E 18.4 (Pages 803 -817); Watch KCV 18.4B, IWE 18.7. Calculate the pH at one-half of the equivalence point. A 30.0-mL sample of 0.165 M propanoic acid ( K. = 1.3 x 10-5) is titrated with 0.300 М КОН. Express your answer using two decimal places. pH Submit Request Answer Part F Calculate the pH at 20 mL of added base.
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