*:This type of moment caused 5 J Bending momet Shear Force Axial Force Torsion
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- Solve for the resultant forces and moments at points A and B in diagram belowAssuming clockwise moment as positive, F = 100 N, T=300 N and P=200 N a) solve for the moment a point A. b) solve for the moment a point B.Refer to the figure below and compute for the moment of force at point C -- (CW+) MC
- solve this without the application of MOMENTS please. the answer is attached alsoFind the summation of forces in x axis and y axis. What is the summation of moments with respect to O, assuming clockwise moment is the positive moment?What is the perpendicular distance from the resultant to point O?If force F= 30i+20j-10k (lb) (a)What is the moment of F about the y-axis? (b) Suppose that you keep the magnitude of F fixed, but you change its direction so as to make the moment of F about the y-axis as large as possible. What is the magnitude of the resulting moment?
- F1 = 250 lbx = 6 fty = 2 fta = 3b = 2Total Moment = 400 lb-ft (counterclockwise) Find the perpendicular moment arm of F (in ft). Find F (in lb).What would be the max value for H if it happens that B can support max a moment with a magnitude of 300KN*m?with the following modifications: Replace the vertical 6kN at point B with a horizontal force 6kN acting to the right at the same point.
- In the figure below, set up an equation related to the moment (M) about the paired force (F).A force F1= 2i – 6k {kN) is applied at the position 3j + 5k {m}, meanwhile another force F2 = - i + 4j + 7k {kN) is applied at the position 8k {m}, on a structure. Evaluate the resultant moment by vector calculationIn the figure, assume clockwise moments as positive, force F=500KN and force P=432 KN. Compute the moment of Force F and P @ points A, B, C, D, E. Calculate the resultant moment @ A and @ B.