Thoroughly mix the aggregate sample and reduce it to an amount suitable for testing, using asample splitter or by quartering. The minimum sample size should be as follows:Minimum Mass, kgFine aggregate with at least 95% passing 2.36-mm sieve0.1Fine aggregate with at least 85% passing 4.75-mm sieve0.5Coarse aggregate with a nominal maximum size of 9.5 mm1Coarse aggregate of a nominal maximum size of 12.5 mm2Coarse aggregate of a nominal maximum size of 19.0 mmCoarse aggregate of a nominal maximum size of 25.0 mm10Coarse aggregate of a nominal maximum size of 37.5 mm15

Sample Splitters: Sample splitters work by reducing the sample size by leading the flow of the…

Answered: Thoroughly mix the aggregate sample and…

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter18: Bituminous Materials

Section: Chapter Questions

Problem 8P: Given four different types of aggregates to be used to produce a blended aggregate for use in the...

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TEST PROCEDURE: 1. Dry the aggregate test sample to a constant weight at a temperature of 110 ± 5°C, then cool to room temperature. 2. Select suitable sieve sizes to furnish the information required by the specifications covering the material to be tested. Common sieves in millimeters are 37.5, 25, 19, 12.5, 9.5, 4.75, 2.36, 1.18, 0.6, 0.3, 0.15, and 0.075 mm (11 2 in., 1 in., 3 4 in., 1 2 in., 3 8 in., No. 4, No. 8, No. 16, No. 30, No. 50, No. 100, and No. 200). 3. Nest the sieves in order of decreasing size of opening, and place the aggregate sample on the top sieve. 4. Agitate the sieves by hand or by mechanical apparatus for a sufficient period. The criterion for sieving time is that, after completion, not more than 1% of the residue on any individual sieve will pass that sieve during 1 minute of continuous hand sieving. 5. Determine the weight of each size increment. 6. The total weight of the material after sieving should be compared with the original weight of the sample placed…
Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have to be blended. The results are as follows:Aggregate A: Bulk specific gravity = 2.491; absorption = 0.8,Aggregate B: Bulk specific gravity = 2.773; absorption = 4.6,a. What is the specific gravity of a mixture of 60% aggregate A and 40% aggregate B by weight?b. What is the absorption of the mixture?
A sieve analysis test was performed on a sample of coarse aggregate and produced the results in Tablea. Calculate the percent passing through each sieve.b. What is the maximum size?c. What is the nominal maximum size?d. Plot the percent passing versus sieve size on a semilog gradation chart.e. Plot the percent passing versus sieve size on a 0.45 gradation chart.f. Referring to Table (ASTM C33), what is the closest size number anddoes it meet the gradation for that standard size?
Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have to be blended. The results are as follows:Aggregate A: Bulk specific gravity = 2.814; Absorption = 0.4% Aggregate B: Bulk specific gravity = 2.441; Absorption = 5.2% a. What is the specific gravity of a mixture of 50% aggregate A and 50% aggregate B by weight? b. What is the absorption of the mixture?
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Calculate the percent voids between aggregate particles that have been compacted by rodding, if the dry-rodded unit weight is 1410 kg/m3and the bulk dry specific gravity is 2.701.
Calculate the bulk specific gravity of combined aggregate if you know the specific gravities of coarse aggregate (C), fine aggregate (F) and Mineral Filler (MF) are 2.61, 2.63 and 2.71 respectively. The percent for C, F, and MF can be determined based on the gradation shown below
A sieve analysis test was performed on a sample of fine aggregate and produced the results in Table below. Calculate the percent passing through each sieve. What is the maximum size? What is the nominal maximum size? What is the Fineness Modulus? Plot the percent passing versus sieve size on a semi-log gradation size. (You can use Excel sheets or you can draw on a semi-log attached to page 3 of this assignment) Sieve size (mm) Amount retained (g) Cumulative amount retained (g) Cumulative percentage retained Percent passing 12.5 0 9.5 21 4.75 104 2.36 79 1.18 78 0.6 51 0.30 78 0.15 82 0.075 39 pan 5
Coarse aggregate is placed in a rigid bucket and compacted with a tamping rod to determineits unit weight. The following data are obtained:• Volume of bucket = 0.5 ft3• Weight of empty bucket = 20.3 lb• Weight of bucket filled with dry compacted coarse aggregate = 76.8 lba) Calculate the dry-compacted unit weight of the aggregate.b) If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids.
1.Calculate for the aggregate impact value given the total weight of aggregates to be 2698 gramsand 45 % of the total weight passed through the 2.36mm sieve and write the nature of thecalculated impact value. 2.An aggregate sample has undergo sieve analysis test. Given the total mass of 1590 grams, theweight of aggregate sample retained on 1.7mm sieve size is 457 grams. Calculate for the abrasionvalue of aggregates. 3.A concrete cylindrical sample has undergone compressive strength test. Given the cross-sectionalfaces of the cylinder each measure 6 inches across, and the cylinder failed at 57,634 pounds of force. What is the compressive strength of that sample of concrete? Please express your answer in N/mm
While measuring the abrasion value of sub-base aggregates category E sample was taken having dry weight of 10000 grams.Amount of fines passing through 1.7 mm sieve was 1550 grams. Workout the abrasion value of aggregates.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 12 ft3Weight of empty bucket = 20.3 lbWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 76.6 lbTrial 2 = 75.1 lb Trial 3 = 78.8 lba. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.

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