Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. m m Applying Newton's second law on the rightmost block: EFx = = ma Applying Newton's second law on the block at the center: IFx - T2- Applying Newton's second law on the leftmost block: ZFx= ma If each block has a mass of 10 kg and is accelerating at 2 m/s, the magnitude of the tension on the second string is 72 = N.

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter4: The Laws Of Motion
Section: Chapter Questions
Problem 13WUE: A block of mass m1= 10 kg is on a frictionless table to the left of a second block of mass m2 = 24...
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Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force F is applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a.

Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so
that each block moves to right with acceleration a.
T2
F
Applying Newton's second law on the rightmost block:
EFx =
= ma
Applying Newton's second law on the block at the center:
EFx =
- T2 =
Applying Newton's second law on the leftmost block:
ZFx=
- ma
If each block has a mass of 10 kg and is accelerating at 2 m/s, the magnitude of the tension on the second string is 72 =
N.
Transcribed Image Text:Three identical blocks of mass m on a frictionless surface are connected by massless taut strings. A force Fis applied on the rightmost block as shown in the figure below so that each block moves to right with acceleration a. T2 F Applying Newton's second law on the rightmost block: EFx = = ma Applying Newton's second law on the block at the center: EFx = - T2 = Applying Newton's second law on the leftmost block: ZFx= - ma If each block has a mass of 10 kg and is accelerating at 2 m/s, the magnitude of the tension on the second string is 72 = N.
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