Ti³+ is to be generated in 0.10 M HCIO for coulometric reduction of azobenzene. TiO²+ + 2H+ + e Ti³+ + H₂O E = 0.100V 4 Ti³+ + C₂H₂N=NCH₂ + 4H₂O → Azobenzene At the counter electrode, water is oxidized, and O₂ is liberated at a pressure of 0.245 bar. Both electrodes are made of smooth Pt, and each has a total surface area of 1.00 cm². The rate of reduction of the azobenzene is 25.9 nmol/s, and the resistance of the solution between the generator electrodes is 46.0 2. Calculate the current density (A/m²) at the electrode surface. current density: 2 CH₂NH₂ + 4 TiO²+ + 4H+ Aniline Use Table 17-1 to estimate the overpotential for O₂ libertation. Table 17-1 Overpotential (V) for gas evolution at various current densities (A/m²) at 25°C 10 A/m² 100 A/m² 1 000 A/m² 10 000 A/m² Electrode Platinized Pt Smooth Pt H₂ 0.0154 0.024 0.721 0₂ H₂ 0₁₂ 0.398 0.0300 0.521 0.068 0.85 02₂ H₂ H₂ 0.0405 0.638 0.0483 0.288 1.28 0.676 0.766 1.49 A/m²

Ti³+ is to be generated in 0.10 M HCIO for coulometric reduction of azobenzene. TiO²+ + 2H+ + e Ti³+ + H₂O E = 0.100V 4 Ti³+ + C₂H₂N=NCH₂ + 4H₂O → Azobenzene At the counter electrode, water is oxidized, and O₂ is liberated at a pressure of 0.245 bar. Both electrodes are made of smooth Pt, and each has a total surface area of 1.00 cm². The rate of reduction of the azobenzene is 25.9 nmol/s, and the resistance of the solution between the generator electrodes is 46.0 2. Calculate the current density (A/m²) at the electrode surface. current density: 2 CH₂NH₂ + 4 TiO²+ + 4H+ Aniline Use Table 17-1 to estimate the overpotential for O₂ libertation. Table 17-1 Overpotential (V) for gas evolution at various current densities (A/m²) at 25°C 10 A/m² 100 A/m² 1 000 A/m² 10 000 A/m² Electrode Platinized Pt Smooth Pt H₂ 0.0154 0.024 0.721 0₂ H₂ 0₁₂ 0.398 0.0300 0.521 0.068 0.85 02₂ H₂ H₂ 0.0405 0.638 0.0483 0.288 1.28 0.676 0.766 1.49 A/m²

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter11: Dynamic Electrochemistry

Section: Chapter Questions

Problem 5P

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