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Tive stresses af the mid Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. ICkness of each layer.

Tive stresses af the mid Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. ICkness of each layer.

Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter5: Soil Improvement And Ground Modification
Section: Chapter Questions
Problem 5.9P
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2. Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq.
SMART al al A 99 |4, 9:52 GLOBE 1. Consider Figure FTR 1 (Taken from Geotechnical Engineer- ing Design, Ming Xiao, strictly for educational purposes) shown. If the specific gravity of the soils are respectively from top to bottom 2.6, 2.7 and 2.73, estimate the effec- tive stresses at the mid thickness of each layer. 2. Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- tion, at the end of the water table, at the interface of the Q = 900 kN Ground surface D, = 1 m Ground water table LX B = 3m x 2m eo = 0.5, c = 0.35, c, = 0.06, ơʻ, = 75 kN/m2 H = 1m H = 9 m H2= 2m eo = 0.48, c. = 0.33, c, = 0.05, ơʻ, = 100 kN/m² eo = 0.45, c = 0.30, c, = 0.05, oʻ, = 180 kN/m2 H3 = 6m clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Figure FTR 1 Average S, Capil- lary Zone G, e D10 Clay 2.71 0.98 0.0125 25 55% Sand 2.74 0.93 N.A. N.A. N.A.
Transcribed Image Text:SMART al al A 99 |4, 9:52 GLOBE 1. Consider Figure FTR 1 (Taken from Geotechnical Engineer- ing Design, Ming Xiao, strictly for educational purposes) shown. If the specific gravity of the soils are respectively from top to bottom 2.6, 2.7 and 2.73, estimate the effec- tive stresses at the mid thickness of each layer. 2. Still considering Figure FTR 1, estimate the additional stress- es induced by the footing on the mid thickness of each layer using both 2-1 approximation and graphical method as proposed by Boussinesq. 3. A soil layer consists of 4 meters of sand underlying 5 meters of clay. The water table is naturally located at the rock bed under the soil strata but rose by 6 meters due to a recent storm. Further, capillary action is expected to de- velop due to the nature of the soil in question. Compute the effective stresses at the end of expected capillary ac- tion, at the end of the water table, at the interface of the Q = 900 kN Ground surface D, = 1 m Ground water table LX B = 3m x 2m eo = 0.5, c = 0.35, c, = 0.06, ơʻ, = 75 kN/m2 H = 1m H = 9 m H2= 2m eo = 0.48, c. = 0.33, c, = 0.05, ơʻ, = 100 kN/m² eo = 0.45, c = 0.30, c, = 0.05, oʻ, = 180 kN/m2 H3 = 6m clay and sand and finally at the bottom of the soil strata. Pertinent soil properties are as follows: Figure FTR 1 Average S, Capil- lary Zone G, e D10 Clay 2.71 0.98 0.0125 25 55% Sand 2.74 0.93 N.A. N.A. N.A.
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