Answer Part 3 Part 1l See Periodic Table O See HintA solution is created by dissolving 12.5 grams of ammonium chloride in enough water to make 255 mL of solution. Howmany moles of ammonium chloride are present in the resulting solution?0.23368moles of NH4C1Part 2See HintWhen thinking about the amount of solute present in a solution, chemists report the concentration or molarity of thesolution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution described above?0.916MPart 3See HintTo carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of thesolution described above will you need to complete the reaction without any leftover NH4CI?0.54585mL of solution

Given: moles of NH4Cl = 0.0500 mol molarity of NH4Cl = 0.916 M

To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4CI? 0.54585 mL of solution

To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the solution described above will you need to complete the reaction without any leftover NH4CI? 0.54585 mL of solution

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 35CR

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Question

Answer Part 3

Part 1
l See Periodic Table O See Hint
A solution is created by dissolving 12.5 grams of ammonium chloride in enough water to make 255 mL of solution. How
many moles of ammonium chloride are present in the resulting solution?
0.23368
moles of NH4C1
Part 2
See Hint
When thinking about the amount of solute present in a solution, chemists report the concentration or molarity of the
solution. Molarity is calculated as moles of solute per liter of solution. What is the molarity of the solution described above?
0.916
M
Part 3
See Hint
To carry out a particular reaction, you determine that you need 0.0500 moles of ammonium chloride. What volume of the
solution described above will you need to complete the reaction without any leftover NH4CI?
0.54585
mL of solution

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