To find the arclength of y = 2x – 3 from = 0 to x = 4, which is the correct integral? OL = V1+ 4x²dx OL = V1+ 4xdx 4 OL = V1+ 16xdx OL = V1 + 16x²dx Now that you have the correct integral, use the substitution u = 4x to re-write the integral in terms of u. Which is the correct result? 16 1 OL = 1+ udu 16 1 OL = V1+ 4udu 16 1 OL = V1+ 2u²du 0. 16 OL = V1+ u*du

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