To find the arclength of y = 4x2 + 1 from x = 0 to x = 5, which is the correct integral? 5 OL = V1 + 8xdx .5 OL= - 64xdx OL = V1 + 64x dæ .5 OL= V1 + 8x? dæ Now that you have the correct integral, use the substitution u = 8x to re-write the integral in terms of u. Which is the correct result? 40 1 OL= 8 V1+ 4u du 40 1 OL= 8 VI+ udu 40 1 OL = 8 V1+ 8udu 40 V1 + u'du 8 OL What is the value of the integral? Hint: Use a table or technology. You may enter a decimal approximation for your solution.

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