To hang a 6.20-kg pot of flowers, a gardener uses two wires—one attached horizontally to a wall, the other sloping upward at an angle of u = 40.0° and attached to the ceiling. Find the tension in each wire.P

Q: Part  a was incorrect please show work and calculation tenision

A: The equations of motion are –

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A: Given Information:- Mass of the block is m1=12 kg Angle of inclination of the surface is θ=24°…

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A: Given: The coefficient of friction is 1/6. m1=2.5 kgm2=2

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A: Given Assuming that the load at C has been removed.(Reference to Problem 4.125):The rigid L-shaped…

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A: Solution attached below

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A: The free body diagram of the system is as shown below:…

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A: Given that,weight of the box= 15 kgcoefficient of sttic friction=0.26

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A:

Q: A 12 kg block rests on a 24 degree inclined frictionless surface and is attached by a light string…

A: The situation is shown in the figure                              There are different kind of the…

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A:

Q: Q.5 An external force F of magnitude F =5N is applied vertically downward on an object of 10 N…

A: Answer               (C) n = 15N

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A: Since there are multiple sub-parts posted, we will answer the first three sub-parts for you. If you…

Q: 270 N 50°7 B 400 N 30 D 30

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A:

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A: Apply Lami's theorem

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A: Magnitude of aerodynamic force (F) = 6250 lb  Angle made with the vertical = 6 degree

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A:

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A: Frictional force, fk=80 N μk=0.30

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A: Given Three cables are used to tether a balloon as shown. Determine the vertical force P exerted by…

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A:

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A: Given Data: For fig. (a) & (b) A cord tension →TA, B cord tension →TB & C cord tension →TC…

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A: Solution:

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A: Free body diagram

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A: (a)The minimum force exerted on the block to avoid slide and the friction force will acts…

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A: two questions is given by you but not informed that which one is to be solved so we will solve 1st…

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A: The free-body diagram of the block with mass m2 is shown below. Here, N denotes the normal force.

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A: Given that:- Mass of block=M kg

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A: Given:Force, F = 22000 Nacceleration, a = 3.5 m/s2

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A:

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A: Given: m=276 kgμs=0.643μk=0.403θ=32.7ϕ=23.0

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A:

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A: Given : weight = 9800 N Upward acceleration = 5 m/s2 Downward acceleration = 5 m/s2

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Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!