To help with the startup costs of his new dental practice, Tony is taking out a $56,000 amortized loan for 10 years at 8.5% annual interest. His monthly payment for this loan is $694.32. Fill in all the blanks in the amortization schedule for the loan. Assume that each month is of a year. Round your answers to the nearest cent. 12 Payment number New loan balance Interest Principal payment payment 1 2 $55,402.59 60 $242.91 $451.41 $33,841.96 61

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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To help with the startup costs of his new dental practice, Tony is taking out a $56,000 amortized loan for 10 years at 8.5% annual interest. His monthly
payment for this loan is $694.32.
Fill in all the blanks in the amortization schedule for the loan. Assume that each month is
of a year. Round your answers to the nearest cent.
12
Principal
payment
New loan
Payment
number
Interest
payment
balance
$ ()
1
$55,402.59
60
$242.91
$451.41
$33,841.96
61
Transcribed Image Text:To help with the startup costs of his new dental practice, Tony is taking out a $56,000 amortized loan for 10 years at 8.5% annual interest. His monthly payment for this loan is $694.32. Fill in all the blanks in the amortization schedule for the loan. Assume that each month is of a year. Round your answers to the nearest cent. 12 Principal payment New loan Payment number Interest payment balance $ () 1 $55,402.59 60 $242.91 $451.41 $33,841.96 61
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