To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 300-loop-per-meter circular coil 0.660 m in radius to create a 1.20-T field (typical of an MRI instrument) at its center with no iron present. The magnetic field of a proton is approximately like that of a circular current loop 0.650×10−15 m in radius carrying 2.1×104 A . What is the field at the center of such a loop?   2.39 x 103 A and 1.02 x 1013 T 2.39 x 10 3 A and 2.04 x 10 13 T   3.183 x 10 3 A and 2.04 x 10 13 T   3.183 x 10 3 A and 1.02 x 10 13 T   None of the above

Q: What is the radius of a proton’s trajectory when it moves at 1.2(10)6 m/s perpendicular to a…

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Q: An ion source is producing 6Li ions, which have charge e and mass 9.99* 10-27 kg. The ions are…

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Q: In the figure, an electron accelerated from rest through potential difference V1=1.26 kV enters the…

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Q: At one instant, v-(-1,93i +2.89j-7.11k) m/s is the velocity of a proton in a uniform magnetic field…

A: As per our policies, I can answer only first three subparts of this question. The solution to these…

Q: In the figure, an electron accelerated from rest through potential difference V1=1.13 kV enters the…

A: V1 = 1.13 kV = 1.13 x 103 V d = 24.3 mm = 0.0243 m V2 = 74.2 V

Q: You are on a team designing a 3.5 T MRI, which is needed by physicians to better diagnose pituitary…

A: Given data- magnetic field B=3.5 T length of machine L=1.4 m maximum current I=150 A

Q: The magnetic moment of the Earth is approximately 8.00 x 1022 A• m2. Imagine that the planetary…

A: Answer (A) Number of unpaired electrons = (8.00× 1022Am2)/(9.27 × 10-24Am2) =…

Q: An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.10 cm in a uniform…

A: Given: Charge of alpha particle, q = +2e = 2 * 1.6 * 10-19 C= 3.2 x 10-19  CRadius of circular path,…

Q: To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the…

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Q: A beam of protons traveling at 1.20 km/s enters a uniform magnetic field, traveling perpendicular to…

A: Velocity of the proton is v = 1.20 km/s Distance traveled by the proton is r = 1.50 cm = 0.015 m…

Q: when a charged particle enters a region of magnetic field traveling in a direction perpendicular to…

A: Magnetic field strength (B) = 0.18 T speed of particle (v) = 12×106 msRadius of trajectory (R) = 106…

Q: An alpha particle with velocity v = (3 x 105 ,0,0) m/s enters a region where the magnetic field…

A: velocity of alpha particle (v) = 300000 m/s along +x direction Magnetic field (B) = 1.2 T along +z…

Q: For a proton to pass undeflected in a region where the field is 0.5 N/C and a magnetic field of 1.25…

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Q: Find the magnetic field (in µT) would be required to constrain an electron whose speed is 20.9x106…

A: Given,

Q: This problem aims to just assist in appreciation of "numbers" related to magnetic interactions.…

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Q: In the figure, an electron accelerated from rest through potential difference V1=1.26 kV enters the…

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Q: If both wires are carrying a current of 7.5 A, what is the magnitude of the magnetic field, in…

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Q: Protons with a kinetic energy of 5 MeV and traveling in the +x-axis direction enter a uniform…

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Q: A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.360 T over a region…

A: Given data: The magnetic field is B=0.36 T. The radius of region is r=2.4 m.

Q: A singly ionized Nickel atom has an overall charge of +1.602 x 10-19 C and a mass, m = 9.80 x 10-26…

A: Given data: The magnitude of charge on atom is q=1.602x10-19 C. The mass of atom is m=9.8x10-26 kg.…

Q: Consider an electron orbiting a proton in a fixed circular orbit of radius R = 5.29 × 1011 by…

A: The centripetal force for the circular motion of the electron must be provided by the electric force…

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A: ANSWER :- like two parallel wires with opposite currents the magnetic force is repulsive.

Q: An alpha particle (q = +2e, m = 4.00 u) travels in a circular path of radius 4.87 cm in a uniform…

A: The relation for the velocity is  v=B q rm The period is given by  T = 2 π mB q The kinetic energy…

Q: In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar…

A: Given data: The thickness of bar is t=0.440 cm. The current in the conductor is I=8 A. The Hall…

Q: An lithium nucleus has a velocity of v = (4.76 x 106 m/s) i – (2.75 x 106 m/s) j and travels through…

A: Given, Velocity, v=4.76×106i-2.75×106j m/s Magnetic field,B=0.66 k T Charge,q=4.806×10-19C…

Q: A deuteron is accelerated from rest through a 10-kV potential difference and then moves…

A: Potential difference =  V = 10kV = 104 V Magnetic field = B = 1.6 T Mass  =  m = 3.3 x 10-27 Kg…

Q: A proton, a deuteron (q=+e, m = 2.0 u), and an alpha particle(q=+2e, m = 4.0 u) all having the same…

A: Here, the magnitude of magnetic force equals the centripetal force. Thus, the equation for the…

Q: A deuteron is accelerated from rest through a 10 kV potential difference and then moves…

A: Given Data The potential difference is V=10 kV The magnitude of magnetic field is Bm=2 T The mass of…

Q: Consider an electron orbiting around a proton with an orbital radius of R = 4.77 · 10 orbital…

A: Given that: R=4.77×10-10 mme=9.11×10-31 kge=1.6×10-19 Ck=9×109 Nm2/C2fo=0.24×1015 Hz

Q: The magnetic moment of the Earth is approximately 8.00 x 1022 A ⋅ m2. Imagine that the planetary…

A: a) The required number of unpaired electron is,

Q: A deuteron is accelerated from rest through a 10 kV potential difference and then moves…

A: Given: The potential difference is 10 kV. The strength of the magnetic field is 3 T. The mass of the…

Q: A proton (charge +e, mass mp), a deuteron (charge +e,mass 2mp), and an alpha particle (charge +2e,…

A: The expression for the radius of proton is,

Q: An alpha-particle (m = 6.64 × 10−27 kg, q = 3.2 × 10−19 C travels in a circular path of radius 25 cm…

A: mass, m = 6.64 × 10−27 kg, charge, q = 3.2 × 10−19 C radius, r = 0.25 m Magnetic field, B = 1.5 T…

Q: In the figure, an electron accelerated from rest through potential difference V1=1.00 kV enters the…

A: V1 = 1000 voltsd = 29.4 mm V2 = 85.9 volts

Q: An alpha particle with velocity v = (3 x 105,0,0) m/s enters a region where the magnetic field has a…

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Q: (I) Alpha particles (charge q = +2e, mass m = 6.6× 10-27 kg) move at 1.6 x 10° m/s. What magnetic…

A: Given data The charge is q=+2e The mass is m=6.6×10-27 kg The speed is v=1.6×106 m/s The radius is…

Q: In an experiment designed to measure the Earth's magnetic field using the Hall effect, a copper bar…

A:

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.