Answered: To what temperature would you have to…

To what temperature would you have to heat Zn(l) to cause its vapor pressure to become 155.9 mm Hg if its heat of vaporization and boiling point are 131.00 kJ/mol and 1180.2 K, respectively?

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter9: Liquids And Solids

Section: Chapter Questions

Problem 98E

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To what temperature would you have to heat Zn(l) to cause its vapor pressure to become 155.9 mm Hg if its heat of vaporization and boiling point are 131.00 kJ/mol and 1180.2 K, respectively?

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