How much energy (kJ) would be required to convert 17.33 g of Pb(s) at its freezing point (327.5 °C) to the boiling point (1740 °C) and then to completely vaporize it? Thermodynamic quantity Value Heat capacity 26.73 J/g*°C Heat of fusion 4.774 kJ/mol Heat of vaporization 195.6 kJ/mol

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter10: Liquids And Solids
Section: Chapter Questions
Problem 141CP: When I mole of benzene is vaporized at a constant pressure of 1.00 atm and at its boiling point of...
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How much energy (kJ) would be required to convert 17.33 g of Pb(s) at its freezing point (327.5 °C) to the boiling point (1740 °C) and then to completely vaporize it?

Thermodynamic quantity

Value

Heat capacity

26.73 J/g*°C

Heat of fusion

4.774 kJ/mol

Heat of vaporization

195.6 kJ/mol
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How was the j/g found at the beginning of the conversion mechanism. The the number is just kind of there with no explanation.

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