Today, the waves are crashing onto the beach every 5.8 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.8 seconds. Round to 4 decimal places where possible.The mean of this distribution is The standard deviation is The probability that wave will crash onto the beach exactly 3.1 seconds after the person arrives is P(x = 3.1) = The probability that the wave will crash onto the beach between 0.9 and 3.4 seconds after the person arrives is P(0.9 < x < 3.4) = The probability that it will take longer than 1.96 seconds for the wave to crash onto the beach after the person arrives is P(x ≥≥ 1.96) = Find the minimum for the upper quartile.  seconds.

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Asked Nov 2, 2019
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Today, the waves are crashing onto the beach every 5.8 seconds. The times from when a person arrives at the shoreline until a crashing wave is observed follows a Uniform distribution from 0 to 5.8 seconds. Round to 4 decimal places where possible.

  1. The mean of this distribution is 
  2. The standard deviation is 
  3. The probability that wave will crash onto the beach exactly 3.1 seconds after the person arrives is P(x = 3.1) = 
  4. The probability that the wave will crash onto the beach between 0.9 and 3.4 seconds after the person arrives is P(0.9 < x < 3.4) = 
  5. The probability that it will take longer than 1.96 seconds for the wave to crash onto the beach after the person arrives is P(x ≥≥ 1.96) = 
  6. Find the minimum for the upper quartile.  seconds.
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Step 2

The probability density function of a uniform distribution over the interval from ‘a’ and ‘b’ is defined below:

It is given that the time from when a person arrives at the shoreline until a crashing wave is observed follow a uniform distribution from 0 to 5.8 seconds.

 

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1 axsb P(X)b-a ; elsewhere That is, a 0 and b= 5.8

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Step 3

1.

The mean of the distribution can be obtained as shown below:

Therefore, the...

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a+b 2 0+5.8 2 5.8 2 - 2.9

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