Transform: F(s) = 6 (s²-4s+20)² 3 f(t) = ³ te cos 4t - e -2t 3 64 16 ○ 3 f(t) = ³4 64 e 2t cos 4t - f(t) = 3 te²t cos 4t 64 3 16 3 ○ f(t) = 3 e²t sin 4t-/te²t cos 4t 64 16 f(t) = 3te²t sin 4t 64 3 f(t)=e-2t sin 4t 64 2t f(t) = 3 e²t cos 4t te²t sin 4t 64 3 16 te 3 16 2t 3 ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ 16 -2t sin 4t 3 f (t) = 3 te-²t sin 4t - 16 e 64 -2t e2t sin 4t 32t cos 4t 16 sin 4t te -2t -2t cos 4t cos 4t

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Related questions
Question
Laplace transform
Transform:
F(s)
=
6
(s²-4s+20)²
3
f(t) = 3 te-2t cos 4t -
64
16
f(t) = 3/4
64
3
64
f(t) = 3/4
64
e
-2t
2t
f(t) = 3/4
64
COS
4t
f(t) = 3 t e²t cos 4t
64
e
3
○
f(t) = e²t sin 4t-te²t cos 4t
16
cos 4t
3
f(t) = 2te²t sin 4t
64
3
f(t) = ³ te-²t sin 4t
64
3
16
-2t sin 4t
3
16
t
3
16
e
e
3
16
3
16
te²t sin 4t
-2t sin 4t
-2t sin 4t
32t cos 4t
16
e2t sin 4t
e
te
-2t
- 2t
cos 4t
cos 4t
Transcribed Image Text:Transform: F(s) = 6 (s²-4s+20)² 3 f(t) = 3 te-2t cos 4t - 64 16 f(t) = 3/4 64 3 64 f(t) = 3/4 64 e -2t 2t f(t) = 3/4 64 COS 4t f(t) = 3 t e²t cos 4t 64 e 3 ○ f(t) = e²t sin 4t-te²t cos 4t 16 cos 4t 3 f(t) = 2te²t sin 4t 64 3 f(t) = ³ te-²t sin 4t 64 3 16 -2t sin 4t 3 16 t 3 16 e e 3 16 3 16 te²t sin 4t -2t sin 4t -2t sin 4t 32t cos 4t 16 e2t sin 4t e te -2t - 2t cos 4t cos 4t
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