TREATMENT Column Name TID PID DNAME TDATE SPECIALTY DataType INT(3) INT(5) VARCHAR(10) VARCHAR(10) DATE Constraint PRIMARY KEY a) Write SQL commands to create the above two database table base on the given field names, data types and constraints required. b) Write an SQL command to change the field length of pname to VARCHAR(20) in the patient table. c) Add a 'problem' column in between DNAME and TDATE in the treatment table. The column will allow VARCHAR(20) as a data type. d) Change column DNAME to Doctor_Name. e) Delete the SPECIALTY column in treatment table.
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- Write a SQL anonymous block to find sum of first ten natural numbers. . Write a SQL function that performs Addition, Subtraction Multiplication and Division of numbers.refer to the given SQL statement CRATE TABLE x(y INT) INSERT INTO x(y) VALUES (1),(2),(3); CREATE VIEW n AS SELECT y FROM x; SELECT y FROM n; What does the last line mean?This actually didnt work to resolve my problem... Heres what I have so far. CREATE TABLE Horse ( ID SMALLINT UNSIGNED AUTO_INCREMENT, RegisteredName VARCHAR(15), PRIMARY KEY (ID)); CREATE TABLE Student ( ID SMALLINT UNSIGNED AUTO_INCREMENT, FirstName VARCHAR(20), LastName VARCHAR(30), PRIMARY KEY (ID)); -- Your SQL statements go here
- /* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…/* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…/* Created with SQL Script Builder v.1.5 */ /* Type of SQL : SQL Server */ CREATE TABLE EMPLOYEE ( EMP_CODE int, EMP_TITLE varchar(4), EMP_LNAME varchar(15), EMP_FNAME varchar(15), EMP_INITIAL varchar(1), EMP_DOB datetime, JOB_CODE varchar(5), STORE_CODE int ); INSERT INTO EMPLOYEE VALUES('1','Mr.','Williamson','John','W','5/21/1964','SEC','3'); INSERT INTO EMPLOYEE VALUES('2','Ms.','Ratula','Nancy','','2/9/1969','MGR','2'); INSERT INTO EMPLOYEE VALUES('3','Ms.','Greenboro','Lottie','R','10/2/1961','GEN','4'); INSERT INTO EMPLOYEE VALUES('4','Mrs.','Rumpersfro','Jennie','S','6/1/1971','GEN','5'); INSERT INTO EMPLOYEE VALUES('5','Mr.','Smith','Robert','L','11/23/1959','GEN','3'); INSERT INTO EMPLOYEE VALUES('6','Mr.','Renselaer','Cary','A','12/25/1965','GEN','1'); INSERT INTO EMPLOYEE VALUES('7','Mr.','Ogallo','Roberto','S','7/31/1962','MGR','3'); INSERT INTO EMPLOYEE VALUES('8','Ms.','Johnsson','Elizabeth','I','9/10/1968','SEC','1'); INSERT INTO EMPLOYEE…
- i have insert a csv into a sql developer databse . there are many nulls like this INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,716INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,717INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,718INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,719INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,720INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,721INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,722INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,723INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,724INSERT INTO NAMES (YEAR, NAME, FREQUENCY, YEAR) VALUES (NULL,'',NULL,NULL);--Row 111,725INSERT INTO NAMES (YEAR, NAME,…You are working with a database table that contains customer data. The table includes columns about customer location such as city, state, country, and postal_code. The state names are abbreviated. You want to check for state names that are greater than 2 characters long. You write the SQL query below. Add a LENGTH function that will return any state names that are greater than 2 characters long.use oracle sql command line with found or notfound method --- with table Customer(customerNo,costomerName ,gender) Employee (employeeNo,employeeName,job) ,branch(No,Name), category(catNo,catogeryName) ___ 4) Create database package pointOfSal which contain the following A. procedure to add new customer which use validation method checkExistingCustomer using cursor to validate customer name if its not exists before, then add this new customer and generate the customer number automatically using database trigger. B. Method to add new Employee which use validation method checkExistingEmployee using cursor to validate Employee name if its not exists before, then add this Employee and generate the Employee number automatically using database trigger. C. procedure to add new Category which use validation method checkExistingCategory using exception to validate category name if its not exists before, then add this category and generate the category number automatically using database…
- Implement the following ER model and sample data using Oracle SQL Developer and your CDM Oracle database account. You will submit a SQL script file and its entire outputs. The table name should be CUSTOMERS (plural). Each CustomerID should be a 3-digit number. Names should be strings of up to thirty characters. The sample data should be: 101, John Doe 102, [Rachel Araya] Order The table name should be ORDERS (plural). Each OrderID should be a 4-digit number. Product names should be strings of up to thirty characters. The sample data should be: 1001, 01-JAN-22, Apple, 101 1002, [a date of your choice], [a product of your choice], 102 PLEASE FOLLOW BELOW The SQL script to (i) drop the two tables, (ii) create the two tables, (iii) insert the sample data, and (iv) show the full contents of the two tables. The header of your script should be something like:/*Your NameIS451 HW5*/ Make sure to start your script file with DROP TABLE commands for the two tables in order to avoid…The following two SQL statements will produce the same results. SELECT P_DESCRIPT, P_QOH,P_PRICE FROM PRODUCT WHERE P_QOH >(SELECT P_QOH FROM PRODUCT WHERE P_CODE='11QER/31') AND P_PRICE>(SELECT P_PRICE FROM PRODUCT WHERE P_CODE='11QER/31'); SELECT P_DESCRIPT, P_QOH,P_PRICE FROM PRODUCT WHERE (P_QOH,P_PRICE) > (SELECT P_QOH,P_PRICE FROM PRODUCT WHERE P_CODE='11QER/31'); A) True B) FalseGiven the following SQL query: Student (sid, name, age, address) Book (bid, title, author) Checkout (sid, bid, date) SELECT S.name FROM Student S, Book B, Checkout C WHERE S.sid = C.sid AND B.bid = C.bid AND B.author = ’Olden Fames’ AND S.age > 12 AND S.age < 20 Write relational algebra query for the above SQL query. Using a drawing tool such as Visio or others (ex: https://www.draw.io/ is a free one) to draw initial relational algebra query trees for the query generated in question 1. Transform the initial query trees created above into a more efficient form (use the heuristic rules and show your steps (.