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Trial 1 2 3 4 5 x² coefficient value from curve fitting 3.32 3.36 4.60 3.28 4.01 Acceleration (m/s²) = 2* (x² coefficient) 6.64 6.72 9.2 6.56 8.02

Trial 1 2 3 4 5 x² coefficient value from curve fitting 3.32 3.36 4.60 3.28 4.01 Acceleration (m/s²) = 2* (x² coefficient) 6.64 6.72 9.2 6.56 8.02

Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 17P: Find the order of magnitude of the number of table-tennis balls that would fit into a typical-size...
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Data Analysis • Average acceleration from table a₁ + a₂ + a² + a₁ + as = aavg 5 • Percent difference with g = 9.8 m/s² |aavg - gl Percent difference X 100% = g Note: Use meters and seconds for all calculations. Show the appropriate units for measured and calculated values
Transcribed Image Text:Data Analysis • Average acceleration from table a₁ + a₂ + a² + a₁ + as = aavg 5 • Percent difference with g = 9.8 m/s² |aavg - gl Percent difference X 100% = g Note: Use meters and seconds for all calculations. Show the appropriate units for measured and calculated values
Trial 1 2 3 4 5 x² coefficient value from curve fitting 3.32 3.36 4.60 3.28 4.01 Acceleration (m/s²) = 2* (x² coefficient) 6.64 6.72 9.2 6.56 8.02
Transcribed Image Text:Trial 1 2 3 4 5 x² coefficient value from curve fitting 3.32 3.36 4.60 3.28 4.01 Acceleration (m/s²) = 2* (x² coefficient) 6.64 6.72 9.2 6.56 8.02
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