Trial 1 Initial Volume Trial 3 Initial Volume 8 9 0 Trial 2 Initial Volume 10 d for thcare Trial 1 Final Volume Trial 2 Final Volume Trial 3 Final Volume 28 29 30 37 38 38 39
Q: Using Le Chatelier, predict the direction of the reaction. 4. 203 (g) 5. H2(g) + + heat F2 (g) 2 HF…
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Q: Using Le Chatelier, predict the direction of the reaction. 4. 203 (g) 5. H2(g) + + heat F2 (g) 2 HF…
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Q: If not, which direction does it need to move (right or left) to reach equilibrium? Explain.
A: For the reaction C6H5NH2(aq)+ H2O (l)------>C6H6NH3+(aq)+OH- Q= reaction coefficient =…
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Q: Consider the reaction 4NH3(g) + 502 (g)→ 4NO₂ (g) + 6H₂O(g) If NO₂ is formed at a rate of 0.0360…
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Q: What changes water from a gas to a liquid phase
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Q: What is the most probable bond angle between O, N, and Cl in the molecule, NOCl? Select one:…
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Q: Calculate the AGᵒrxn using the following information at 25 °C 7 N₂(g) + H₂O(1) HNO3(g) + N₂H4(1)…
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Q: 4. Give synthesis O H3CN- H3CH₂C -NH₂
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Q: Consider the peptides below. Peptide 1: Peptide 2: NH₂ Luasiya H₂N pro-ile-glu-arg How many peptide…
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Q: Calculate the heat of reaction for the reaction 25+ 2 OF 2(g) → SO₂ + SF (g) 2(g) using the…
A: Data given: OF2 (g) + H2O (l) → O2 (g) + 2 HF (g) ΔH° = −277 kJ ------------ (1) SF4(g) + 2…
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- What is the density of the vinegar sample used? TRIAL 1 TRIAL 2 TRIAL 3 Wt. of vinegar sample 8.2000 g 8.1000 g 8.2500 g Vol. of vinegar sample 10.00 mL 10.00 mL 10.00 mLChemistry Fraction no. Elution Vol. (mL) Abs (λ = 410) Fraction no. Elution Vol. (mL) Abs (λ = 410) 1 (PB pH 6.0) 1 0.0050 11 11 0.0041 2 2 0.0032 12 12 0.0060 3 3 0.0040 13 13 0.0064 4 4 0.0064 14 14 0.0063 5 5 0.0067 15 15 0.1109 6 6 0.0067 16 16 2.8902 7 7 0.0050 17 17 0.8500 8 (PB pH 8.0) 8 0.0049 18 18 0.2019 9 9 0.0052 19 19 0.0378 10 10 0.0050 20 20 0.0073 Use the data above to plot an elution profile, in which the absorbance is on Y-axis, and elution volume (volume = fraction number) is on X-axis. The elution profile must indicate at (1) which point the pH change occurred, (2) the fraction(s) which contain the highest myoglobin content, and (3) the maximum absorbance detected.how would I start a Dixon Q test with 3 variables: Initial Volume (mL) 0.2 0.1 0.1 Final Volume (mL) 17.5 17.1 17.0
- Trial 1 2 3 Height (cm) 6.50 6.45 6.44 Diameter (cm) 1.25 1.26 1.22 Mass (g) 46.683 46.332 47.014 Volume (cm^3) 7.98 8.04 7.52 Density (g/cm^3) 5.85 5.76 6.25 AVERAGE DENSITY: 5.95 g/cm^3 ACCEPTED VALUE FOR DENSITY: 6.70 g/cm^3 PERCENT RELATIVE ERROR: 11.2% Are these measurements more precise or more accurate? Explain.Q = ([Li+]6 [Cl-]6)/([SmCl3]2) = (0.01006 * 0.01006)/(2.002) = 2.5 x 10-18 this calculation is wrong its 2.5 X 10-25A piece of foam has a mass of 24.3g and a volume of 7.21 x1^5 mm^3. What is the density of the foam in g/cm^3? Report answer in thousandths place
- 1. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(8.50mL-8.74mL)2+(9.72mL-8.74mL)2+(8.00mL-8.74mL)2/(3-1)]½ 2. σ=[(Σd2)/(n-1)]½ n= number of trials d= measured value - mean σ=[(10.69-11.52)2+(11.80-11.52)2+(12.07-11.52)2/(3-1)]½Table 5.5 (data)ObservationsSample Tested Add HCISolid CaCO 3 _______Solid CuSo 4 _______Mixture _______Filtrate _______Solid fromfunnel _______Seconds(s) Tap H2OTemp (°C) Salt Solution(+ 2.5 mL salt)Temp (°C) Salt Solution(+ 5 mL salt)Temp (°C) 30 9 7 0 60 4 4 -1 90 3 2 -2 120 2 1 -2 150 1 1 -2 180 1 1 -2 210 1 1 -2 240 1 1 -2 270 1 1 -2 300 1 1 -2 330 1 1 -2 360 1 1 -2 390 1 1 -2 420 1 1 -3 450 1 1 -3 480 1 1 -3 510 1 1 -3 540 1 1 -3 570 1 1 -3 600 1 1 -3 Attach three (virtual) graphs. On one graph, plot the data from the tap water. On the other two graphs, plot the data from the salt solutions. Clearly label the freezing point on each graph.
- How many miles Ca(MnO4)2 are represented in 89,000,000,000,000,000,000,000 formula units of Ca(MnO4)2? Show work using the dimensional analysis and units? Give numeric answerpls complete the 2nd table given the data1. 500.0 mL 0.2 M KI2. 500.0 mL 0.2 M KCl3. 500.0 mL 0.1 M K2S2O84. 500.0 mL 0.1 M K2SO45. 500.0 mL 4.0 mM Na2S2O3 (from Na2S2O3∙5H2O)Which substance should go at the bottom of the fraction ration and which should go on the top ? 0.37 mol H2(--------) Which answer choice ? 2NH3 at the top N2 at the bottom 2NH3 at the top 3H2 at the bottom 3H2 at the top 2NH3 at the bottom N2 at the top 2NH3 at the bottom