trial 1 trial 2 trial 3 short side torque (Nm) "expected value" (same as above) (same as above) total long side torque (Nm) "measured value" % error

College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter8: Rotational Equilibrium And Rotational Dynamics
Section8.5: Relationship Between Torque And Angular Acceleration
Problem 8.2QQ: A constant net torque is applied to an object. Which one of the following will not be constant? (a)...
icon
Related questions
Question
3
trial 1
trial 2
trial 3
*
15
Y
V
short side torque (Nm)
"expected value"
(same as above)
O Et
%5
(same as above)
G
B
6
H
total long side torque (Nm)
"measured value"
99+
N
M
K
% error
6
52°F Clear
9:54 PM
11/27/2022
Transcribed Image Text:3 trial 1 trial 2 trial 3 * 15 Y V short side torque (Nm) "expected value" (same as above) O Et %5 (same as above) G B 6 H total long side torque (Nm) "measured value" 99+ N M K % error 6 52°F Clear 9:54 PM 11/27/2022
E
Position of the new pivot:
short side
(all trials)
long side
(trial 1)
long side
(trial 2)
long side
(trial 3)
meter stick
center of mass
(all trials)
*
7
4
Y
mass
20.74 g + 200 g =
kg
20.90 g +100 g =
O
kg
20.90 g + 30 g =
V
Lab 10: Torque and Equilibrium
Assignment
%
kg
20.90 g + 10 g =
5
100
70.58 g =
kg
T
30.00 cm
kg
B
weight (N)
I
position
15.00 cm
45.50 cm
66.90 cm
90.75 cm
50.20 cm
(99+
N
기
lever arm (m)
30.00 - 15.00 cm =
45.50-30.00 cm =
66.90-30.00 cm =
90.75-30.00 cm
P
50.20-30.00 cm T
M
K
torque (Nm)
20
52°F Clear
9:54 PM
11/27/2022
Transcribed Image Text:E Position of the new pivot: short side (all trials) long side (trial 1) long side (trial 2) long side (trial 3) meter stick center of mass (all trials) * 7 4 Y mass 20.74 g + 200 g = kg 20.90 g +100 g = O kg 20.90 g + 30 g = V Lab 10: Torque and Equilibrium Assignment % kg 20.90 g + 10 g = 5 100 70.58 g = kg T 30.00 cm kg B weight (N) I position 15.00 cm 45.50 cm 66.90 cm 90.75 cm 50.20 cm (99+ N 기 lever arm (m) 30.00 - 15.00 cm = 45.50-30.00 cm = 66.90-30.00 cm = 90.75-30.00 cm P 50.20-30.00 cm T M K torque (Nm) 20 52°F Clear 9:54 PM 11/27/2022
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Angular speed, acceleration and displacement
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781285737027
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill
College Physics
College Physics
Physics
ISBN:
9781938168000
Author:
Paul Peter Urone, Roger Hinrichs
Publisher:
OpenStax College
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning