Trial [A]o [B]o [Clo Rate 1 0.10 0.20 0.30 0.063 2 0.30 0.40 0.20 0.084 3. 0.60 0.40 0.20 0.168 4 0.30 0.40 0.10 0.021 0.60 0.20 0.20 0.168 What is the correct rate law? A = k[A][B][C] Rate = k[A][B][C]? C Rate = K[A][C]? Rate = k[A]°[B]?[C]
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- Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?)[A] (M) [?] (?)[B] (M) Rate (M/s) 1 0.360 0.330 0.0164 2 0.360 0.660 0.0164 3 0.720 0.330 0.0656 ?=? Units =?Determine the average rate of change of BB from ?=0 st=0 s to ?=272 s.t=272 s. A⟶2BA⟶2B Time (s) Concentration of A (M) 0 0.7300.730 136136 0.4450.445 272272 0.1600.160 rateB= __________M/sUsing the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?) [?] (?) Rate (M/s) 1 0.360 0.290 0.0144 2 0.360 0.580 0.0144 3 0.720 0.290 0.0576 k=
- Using the data in the table, determine the rate constant of the reaction and select the appropriate units. A+2B⟶C+D Trial [?] (?) [?] (?) Rate (M/s) 1 0.340 0.210 0.0204 2 0.340 0.420 0.0204 3 0.680 0.210 0.0816 ?=The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (A) If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed?Consider the reaction A(g) + 2B(g) → 2C(g) + 2D(g) and associated that was collected at a constant temperature. Trial Initial [A] Initial [B] Initial Rate (mol/L) (mol/L) (mol/(L·min)) 1 0.125 0.200 7.25 2 0.375 0.200 21.75 3 0.250 0.400 14.50 4 0.375 0.400 21.75 What is the rate law?
- Consider the reaction A(g) + 2B(g) → 2C(g) + 2D(g) and associated that was collected at a constant temperature. Trial Initial [A] Initial [B] Initial Rate (mol/L) (mol/L) (mol/(L·min)) 1 0.125 0.200 7.25 2 0.375 0.200 21.75 3 0.250 0.400 14.50 4 0.375 0.400 21.75How can I find the numeric value of the rate constant for the following experiments? Experiment 1: .0010 M NO2, .0050 M F2; initial rate= 2.0 x 10^-4 molF2/ L x s Experiment 2: .0020 M NO2, .0050 M F2; initial rate= 4.0 x 10^-4 molF2/L x s Experiment 5: .0010 M NO2, .0010 M F2; initial rate= 4.0 x 10^-5 molF2/L x s1. The decomposition of aqueous sucrose to form the isomers glucose and fructose is a common organic reaction, which requires a strong catalyst: C12H22O11(aq) + H2O(l) → 2C6H12O6(aq). The following data were collected during the process: Time (min) [C12H22O11] (mol/L) 0 0.316 39 0.274 80 0.238 140 0.190 210 0.146 (a)If we performed a new trial with an initial concentration of sucrose of 0.400 mol/L, what concentration would remain after 4.0 h has passed? 2. Methyl isomerizes to acetonitrile, CH3NC(g) → CH3CN(g) at 215°C. The following data were collected during the process: Time (sec) [CH3NC] (mol/L) 2000 0.0110 5000 0.0059 8000 0.0031 12000 0.0014 15000 0.0007 2. (a)Assuming the process continues, what concentration of methyl isonitrile would we expect after 5.00 h?
- Based on the information below, determine the rate law. N2 + O2 --> 2 NO [N2] (M) [O2] (M) initial rate (M/s) Exp 1 0.040 0.020 707 Exp 2 0.040 0.010 500 Exp 3 0.010 0.010 125EXP [NO]-1/m [H2] .1M initial rate/ ms-1 1 0.10 0.10 1.23x10-3 2 0.10 0.20 1.23 x 10-3 3 0.20 0.10 4.92 x 10-3 calculate the rate when [NO] = 0.050M and [H2]=0.150MRate Law find the initial rate N2O4 - 2 NO2 experiment initial (N2O4) (M) initial rate (M/sec) 1 0.50 0.050 2 1.00 0.200 3 1.50 0.450