Answered: True/False A7 The cost of underground…

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Electrical Engineering

True/False A7 The cost of underground cable is much more than that of overhead conductor.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter4: Transmission Line Parameters

Section: Chapter Questions

Problem 4.5MCQ: Shield wires located above the phase conductors protect the phase conductors against lightning. True...

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Concept explainers

Photoelectric

The photoelectric effect occurs when light (or similar incident radiation, including X-rays) falls on material together with a metal plate and causes it to emit electrons. The discovery of the photoelectric effect led to important new theories (and to a Nobel Prize for Albert Einstein). Photoelectric cells, or photocells, are utilized in burglar-alarm light detectors and garage-door openers (each employs a through-beam of light this is broken when something movements throughout it), and also to play soundtracks on film movies (in which a light beam shines through the soundtrack encoded at the film and is "read" with the aid of the photocells).

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A7
The cost of underground cable is much more than that of overhead conductor.

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a. What is the ampere rating of circuit A16? _________________ b. What is the conductor size of circuit A16? _________________
Overhead transmission-line conductors are bare with no insulating cover. (a) True (b) False
What are the colors of the conductors in nonmetallic-sheathed cable for a. 2-wire cable? _______________, _______________ b. 3-wire cable? _______________, _______________, _______________
Transmission line conductance is usually neglected in power system studies. True False
For either single-phase two-wire line or balanced three-phase three-wire line with equal phase spacing D and with conductor radius r, the capacitance (line-to-neutral) in F/m is given by Can=.
For the overhead line of configuration shown in Figure 4.33 operating at 60 Hz and a conductor temperature of 700C, determine the resistance per phase, inductive reactance in ohms/mile/phase, and the current-carrying capacity of the overhead line. Each conductor is ACSR Cardinal of Table A.4.
A 60-Hz, 765-kV, three-phase overhead transmission line has four ACSR 900 kcmil 54/3 conductors per phase. Determine the 60 Hz resistance of this line in ohms per kilometer per phase at 50C.
A three-phase overhead transmission line is designed to deliver 190.5 M VA at 220 kV over a distance of 63 km, such that the total transmission line loss is not to exceed 2.5 of the rated line MVA. Given the resistivity of the conductor material to be 2.84108-m, determine the required conductor diameter and the conductor size in circular mils. Neglect power losses due to insulator leakage currents and corona.
Shield wires located above the phase conductors protect the phase conductors against lightning. True False
For the case of double-circuit, bundle-conductor lines, the same method indicated in Problem 4.27 applies with r' replaced by the bundles GMR in the calculation of the overall GMR. Now consider a double-circuit configuration shown in Figure 4.36 that belongs to a 500-kV, three-phase line with bundle conductors of three subconductors at 21 in. spacing. The GMR of each subconductor is given to be 0.0485 ft. Determine the inductive reactance of the line in ohms per mile per phase. You may use XL=0.2794logGMDGMR/mi/phase
For a single-phase, two-wire line consisting of two solid cylindrical conductors of same radius, r, the total circuit inductance, also called loop inductance, is given by (in H/m) 2107ln(Dr) 4107ln(Dr) where r=e14r=0.778r
Figure 4.34 shows double-circuit conductors' relative positions in segment I of transposition of a completely transposed three-phase overhead transmission line. The inductance is given by L=2107lnGMDGMRH/m/phase Where GMD=(DABeqDBCeqDACeq)1/3 With mean distances defined by equivalent spacings DABeq=(D12D12D12D12)1/4DBCeq=(D23D23D23D13)1/4DACeq=(D13D13D13)1/4 And GMR=[ (GMR)A(GMR)B(GMR)C ]1/3 with phase GMRs defined by (GMR)A=[ rD11 ]1/2;(GMR)B=[ rD22 ]1/2;(GMR)C=[ rD33 ]1/2 and r is the GMR of phase conductors. Now consider a 345-kV, three-phase, double-circuit line with phase-conductors GMR of 0.0588 ft and the horizontal conductor configuration shown in Figure 4.35. Determine the inductance per meter per phase in Henries (H). Calculate the inductance of just one circuit and then divide by 2 to obtain the inductance of the double circuit.