Tube 3 did not have starch or amylase in it. Why did it show a positive reaction with the Benedict's test? Benedict's reagent reacts with maltose maltose was broken down into starch by the acidic environment Benedict's reagent reacts with the pH 7 buffer Benedict's reagent reacts with water
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- 1. Seliwanoff's test uses 6M HCl as dehydrating agent and resoncinol as condensation reagent. The test reagent dehydrates ketohexoses to produce a a. green compound b. violet precipitate c. faint pink color d. cherry red product 2. Bial’s test reacts with hexoses yield a a. red or pink product b. brown to grey product c. blue to purple color d. white precipitate 3. Bial’s test uses concentrated HCl as a dehydrating acid and orcinol + traces of ferric chloride as condensation reagent. The test reagent dehydrates pentoses to form furfural. Furfural further reacts with orcinol and the iron ion present in the test reagent to produce a a. bluish or green product b. red precipitate c. yellow solution d. light pink or pink solution 4. The copper sulfate (CuSO4) present in Benedict's solution reacts with electrons from the aldehyde or ketone group of certain sugars to form a carboxylic acid and a a. reddish…PRODUCTS. Match the name of the product with the biochemical reaction. Products may be used more than once. Tests may require more than one answer.a. 2,3-butanediol 1.catalase b. ammonia 2.phenylalanine deamination c.fatty acids 3.triglyceride hydrolysis d. indole 4.tryptophan degradation e.molecular oxygen 5.urea hydrolysis f. phenylpyruvic acid 6.Voges-Proskauer testWhen some sugars dissolve in water they spontaneously undergo changes in optical rotation called mutarrotation. The Mutarrotation of D-glucopyranose is catalyzed by acid and bases. 2-Hydroxypyridine is a more effective catalyst than phenol and pyridine for this reaction because: a.Both oxygen and N in 2-hydroxypyridine act as bases increasing the rapid interconversion of sugar b. The OH of 2-hydroxypyridine serves as the base while the current N as the acid. c. 2-hydroxypyridine acts both as a base to remove the proton from the hydroxyl group in the hemiacetal and as an acid to provide a proton to the oxygen in the hemiacetal. d.Phenol and pyridine are very expensive.
- 2. Write: why saccharose is a non-reducing disaccharide. 3. Write the equations of reactions:3.1 glucose +Ag2O(NH3)→;3.2 glucose +H2→;3.3 α-D-glucopyranose +CH3OH(HCl)→;3.4 β-D-glucopyranose +(CH3CO)2O→;3.5 maltose hydrolysis;3.6 glucaric acid formation from glucose.Why is –NHCH3 an activator during SEAr, but a deactivator during SNAr?Draw the structure of the products formed when Arabinose shown above undergoes the following reaction: Tollen's reagent (include side product) Benedict's reagent (include side product) Oxidizing enzyme to produce alduronic acid Reducing agent like NaBH4 with Ethylamine (CH3CH2NH2) do everything for upvote
- 1.Explain what is anomeric effect and why it happens? 2.Explain how a glycosyl acetimidate can loss its glycosyl donor activity?for qualitative test for reducing sugar, write the balanced chemical equation and identify the product that gives the positive result. Include the observable change that indicates the positive result. Test for Reducing Sugars 1. Put 10 drops of hydrolysates into eight different test tubes. Test the acidity of each sample. Neutralize with solid Na2CO3 (for acidic samples) or 1.00 M HCl (for basic samples). 2. To 5 drops of the neutralized hydrolysates, add 4 drops of Benedict’s reagent. 3. Put 10 drops of unhydrolyzed samples into two different test tubes and add 4 drops of Benedict’s reagent. 4. Heat all tubes in a boiling water bath until brick red precipitates form or until no further change occurs. Note the time required by each tube to attain the positive result.Draw the products formed when D-arabinose is treated with each reagent: (a) Ag2O, NH4OH; (b) Br2, H2O; (c) HNO3, H2O.
- 1. The process of purifying soap by adding excess NaCl is called_________* Salting-in Salting-out Saponification Hydrolysis 2. Heating of the mixture of ribose and Bial's reagent cherry red complex brick red precipitate purple junction blue-green product no reaction 3.Adding Molisch reagent to starch and layered with sulfuric acid cherry red complex brick red precipitate purple junction blue-green product no reactionReaction a) maltose (s) + H2O (l) -----> 2 glucose (s) Reaction b) 6 CO2 (g) + 6 H2O (l) -------> glucose (s) + 6 O2 (g) How would you manipulate reactions a) and b) to ended up with the reaction c) ? Reaction c) maltose (s) + 12 O2 (g) -------> 12 CO2 (g) + 11 H2O (l) Step by step : What needs to be done to the reaction a) ? What needs to be done to the reaction b)? Add new reactions a) and b) together to prove that you ended up with the reaction c)i would like to ask the following questions: 1. Aside from the reagent and the positive results, what is the difference between Fehling’s Test, Moore’s test and Benedict’s Test if they are all used to detect the presence of reducing sugar?2. In Benedict’s Test, why are there different colors? Why not just one color in varying shades?3. Why is sucrose not a reducing sugar even though most disaccharides are reducing sugars?