Tutorial Exercise The heating element of a coffeemaker operates at 120 V and carries a current of 3.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.692 kg of water from room temperature (23.0°C) to the boiling point. Step 1 The energy required to raise the temperature of an amount of water of mass mw from T; = 23.0°C to the boiling point, T = 100°C, is Q = m„C„(AT), where the specific heat of water c, = 4186 J/kg · °C. We have Q = m,C„(AT) = mC„(T – T;) .692 0.692 kg) (4186 J/kg · °c)77 77 °C) = 2.23 2.23 x 105 J. Step 2 The rate P at which the heating element converts electrical potential energy into the internal energy of the water is P = (AV)I = J/s.
Tutorial Exercise The heating element of a coffeemaker operates at 120 V and carries a current of 3.70 A. Assuming the water absorbs all of the energy converted by the resistor, calculate how long it takes to heat 0.692 kg of water from room temperature (23.0°C) to the boiling point. Step 1 The energy required to raise the temperature of an amount of water of mass mw from T; = 23.0°C to the boiling point, T = 100°C, is Q = m„C„(AT), where the specific heat of water c, = 4186 J/kg · °C. We have Q = m,C„(AT) = mC„(T – T;) .692 0.692 kg) (4186 J/kg · °c)77 77 °C) = 2.23 2.23 x 105 J. Step 2 The rate P at which the heating element converts electrical potential energy into the internal energy of the water is P = (AV)I = J/s.
Physics for Scientists and Engineers
10th Edition
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Direct-current Circuits
Section27.4: Rc Circuits
Problem 27.5QQ: Consider the circuit in Figure 27.17 and assume the battery has no internal resistance. (i) Just...
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