Tutoriar Exercise Consider the following figure. 7.00 N 4.00 N 9.00 R a b (a) Find the equivalent resistance between points and b in the figure. (R = 15.5 N) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter28: Direct-current Circuits
Section: Chapter Questions
Problem 28.5P: Three 100- resistors are connected as shown in Figure P28.5. The maximum power that can safely be...
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Tutorial Exercise
Consider the following figure.
7.00 N
4.00 N
9.00 N
R
a
b
(a) Find the equivalent resistance between points a and b in the figure. (R = 15.5 2)
(b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b.
Step 1
(a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the
figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure.
4.00 N
Red
9.00 N
Transcribed Image Text:Tutorial Exercise Consider the following figure. 7.00 N 4.00 N 9.00 N R a b (a) Find the equivalent resistance between points a and b in the figure. (R = 15.5 2) (b) Calculate the current in each resistor if a potential difference of 27.0 V is applied between points a and b. Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N
Step 1
(a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the
figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure.
4.00 N
Red
9.00 N
For the equivalent resistance, we have
-1
1
Rcd =
Ω.
7.00 N
Ω
This resistance is in series with the 4.00-2 and the 9.00-2 resistors as shown in the diagram in this step. Let R, represent the 4.00-2 resistance and Ro the
9.00-2 resistance. The total resistance Rh between points a and b is then
Rab = R4 + Rcd + R9
=4.00 Ω+
2 + 9.00 Q =
Ω.
Submit
Skip (you cannot come back)
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Transcribed Image Text:Step 1 (a) The 7.00-N and the R = 15.5 2 resistors between points c and d in the figure above are connected in parallel with each other. Thus we can redraw the figure, as shown in the diagram below where Red is the equivalent resistance between points c and d in the original figure. 4.00 N Red 9.00 N For the equivalent resistance, we have -1 1 Rcd = Ω. 7.00 N Ω This resistance is in series with the 4.00-2 and the 9.00-2 resistors as shown in the diagram in this step. Let R, represent the 4.00-2 resistance and Ro the 9.00-2 resistance. The total resistance Rh between points a and b is then Rab = R4 + Rcd + R9 =4.00 Ω+ 2 + 9.00 Q = Ω. Submit Skip (you cannot come back) Need Heln? Read It
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