Two charges are placed as shown in the figure. The distance between charges is 13.0 cm Point P is 5.0 cm from the charge q1 and 12.0 cm from the charge g2. The magnitude of q is 3.00 pC, but its sign and the value of the charge g2 are not known. The direction of the net electric field E at point P is entirely in the negative y-direction. (Figure 1) What is the sign of q2? positive negative Previous Answers Submit Correct Part C Figure 1 of 1 Determine the magnitude of E. VOA¢ P E 1168.7 N/C 12.0 cm 5.0 cm Previous Answers Request Answer Submit XIncorrect; Try Again; 4 attempts remaining 13.0 cm 92 13 cm gne + om sine + E(ostoE Sin@o2)E EEE(oESnAlat 3X + C+D=9O 13 10earcdenE Honfy २२५
Two charges are placed as shown in the figure. The distance between charges is 13.0 cm Point P is 5.0 cm from the charge q1 and 12.0 cm from the charge g2. The magnitude of q is 3.00 pC, but its sign and the value of the charge g2 are not known. The direction of the net electric field E at point P is entirely in the negative y-direction. (Figure 1) What is the sign of q2? positive negative Previous Answers Submit Correct Part C Figure 1 of 1 Determine the magnitude of E. VOA¢ P E 1168.7 N/C 12.0 cm 5.0 cm Previous Answers Request Answer Submit XIncorrect; Try Again; 4 attempts remaining 13.0 cm 92 13 cm gne + om sine + E(ostoE Sin@o2)E EEE(oESnAlat 3X + C+D=9O 13 10earcdenE Honfy २२५
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter23: Electric Forces
Section: Chapter Questions
Problem 29PQ: Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric...
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My problem is related to electric fields, as the picture shows. I tried decomposing each of the forces of the charges, setting the horizontal components equal, solving for q2, and then adding the vertical components.
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