Two individuals are heterozygous for a rare disorder and have two children. What is the probability that both children will be phenotypically normal (i.e. not homozygous recessive and therefore not manifesting the disorder)?

Two individuals are heterozygous for a rare disorder and have two children. What is the probability that both children will be phenotypically normal (i.e. not homozygous recessive and therefore not manifesting the disorder)?

Name: Two individuals are heterozygous for a rare disorder and have two chi
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: Two individuals are heterozygous for a rare disorder and have two children. What is the probabilitythat both children will be phenotypically normal (i.e. not homozygous recessive and therefore notmanifesting the disorder)?O 0.66O 0.75O e. 0.00O 0.25

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 8SQ

See similar textbooks

Similar questions

Monozygotic (MZ) twins have a concordance value of 44% for a specific trait, whereas dizygotic twins have a concordance value of less than 5% for the same trait. What could explain why the value for MZ twins is significantly less than 100%?
The percentage of individuals exhibiting a recessive disease in apopulation is 0.04, which is 4%. Based on the Hardy-Weinbergequation, what percentage of individuals would be expected to beheterozygous carriers?
There are two alleles for the height gene, T for tall and t for short. One parent is a heterozygote, while the other is a recessive homozygotes. Which genotypes, and at which frequencies, are possible from these two parents. a.) 100% heterozygotes b.) 100% dominant homozygotes c.) 50% dominant homozygotes, 50% recessive homozygotes d.) 50% dominant homozygotes, 50% heterozygotes e.) 50% heterozygotes, 50% recessive homozygotes f.) 25% dominant homozygotes, 50% heterozygotes, 25% recessive homozygotes g.) 100% recessive homozygotes
If RR stands for red, RR' stands for roan and R'R' stands for white; as well as B stands for bucking, which is dominant over b which is easy riding, what will be the chance of getting a roan, easy riding horse from a cross between 2 roan, heterozygous bucking horses? 9/16 1/8 1/4 3/16
If both parents are carriers for an autosomal recessive disorder (i.e. both Aa) and they have 2 children, what is the probability that both will be affected by the disorder? (Give your answer to 4 decimal places)"
A disease is known to be inherited through an ADHL mode of inheritance. For a pairing of two affected individuals, what is the expected proportion of offspring that will be affected AND female? a. 0.25. b. 0.125. c. 0.667. d. 0. e. 0.333.
Assume that attached earlobes is an autosomal recessive trait with 47% penetrance. If one parent is heterozygous (Aa) and the other homozygous recessive (aa) for the attached earlobe gene, what is the probability that their first child will have attached earlobes? Show calculations please! a. 50%b. 11.75%c. 25%d. 23.5%e. 74%
The genotypic ratio is 1 FF: 2 Ff: 1 ff, or simply 1:2:1, butthe phenotypic ratio is 3:1. Why?
In mating between two individuals that are heterozygous for a recessive allele, what genotypic ratio would you expect in the offspring? homozygous dominant: heterozygous: homozygous recessive? A. 1:2:1 B. 3:1:1 C. 1:2:0 D. 0:2:1 E. 1:4:2
If RR stands for red, RR' stands for roan and R'R' stands for white; as well as B stands for bucking, which is dominant over b which is easy riding, what will be the chance of getting a white, bucking horse from a cross between 2 roan, heterozygous bucking horses? 1/8 3/16 1/16 1/4
What proportion of the F2 individuals would you expect to be homozygous following a dihybrid cross? (A homozygote for two separate genes may be homozygous dominant for both genes, or homozygous recessive for both genes, or homozygous dominant for one gene and homozygous recessive for the other gene.) One half One third One quarter One eighth One sixteenth
Blood type is determined by multiple codominant alleles of the I gene, IA, IB, and i, where ii results in type O. The genotypes of a husband and wife are IAIB x IAi. Among the blood types of their children, how many different genotypes and phenotypes are possible? Group of answer choices 2 genotypes, 3 phenotypes 4 genotypes, 3 phenotypes 3 genotypes, 3 phenotypes 3 genotypes, 4 phenotypes