Two steel springs arranged in series supports a load P. The upper spring has 12 turns of 20-mm-diameter wire on a mean radius of 100 mm. The lower spring consists of 10 turns of 25-mm diameter wire on a mean radius of 75 mm. If the maximum shearing stress in either spring must not exceed 300 MPa, compute the maximum value of P and the total elongation of the assembly. Use approximation formula and G = 83 GPa. Compute the equivalent spring constant by dividing the load by the total elongation.
Two steel springs arranged in series supports a load P. The upper spring has 12 turns of 20-mm-diameter wire on a mean radius of 100 mm. The lower spring consists of 10 turns of 25-mm diameter wire on a mean radius of 75 mm. If the maximum shearing stress in either spring must not exceed 300 MPa, compute the maximum value of P and the total elongation of the assembly. Use approximation formula and G = 83 GPa. Compute the equivalent spring constant by dividing the load by the total elongation.
Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter3: Torsion
Section: Chapter Questions
Problem 3.7.3P: A motor driving a solid circular steel shaft with diameter d = 1.5 in, transmits 50 hp to a gear at...
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Two steel springs arranged in series supports a load P. The upper spring has 12 turns of 20-mm-diameter
wire on a mean radius of 100 mm. The lower spring consists of 10 turns of 25-mm diameter wire on a
mean radius of 75 mm. If the maximum shearing stress in either spring must not exceed 300 MPa,
compute the maximum value of P and the total elongation of the assembly. Use approximation formula
and G = 83 GPa. Compute the equivalent spring constant by dividing the load by the total elongation.
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