OH, 44824 419-684-5402Course: MATHCR Geometry vUnit: Unit 16: Similar Figures12) A rectangle has sides of 72 cm and 36 cm. Another rectangle has sides of 4 cm and 8 cm. What is the scaleratio?Read aOA) 9:1OB) 8:1OC) 7:2OD) 5:3UnitAnswerQuestionsSaveNot GradedSplitScreenSplitScreenDecide if each pair of polygons are similar for questions 13 - 17.UnitResources

UH, 44824 419-684-5402 Course: MATHCR Geometry Unit: Unit 16: Similar Figures 12) A rectangle has sides of 72 cm and 36 cm. Another rectangle has sides of 4 cm and 8 cm. What is the scale ratio? OA) 9:1 OB) 8:1 OC) 7:2 OD) 5:3 Save Not Graded Decide if each pair of polygons are similar for questions 13 - 17.

UH, 44824 419-684-5402 Course: MATHCR Geometry Unit: Unit 16: Similar Figures 12) A rectangle has sides of 72 cm and 36 cm. Another rectangle has sides of 4 cm and 8 cm. What is the scale ratio? OA) 9:1 OB) 8:1 OC) 7:2 OD) 5:3 Save Not Graded Decide if each pair of polygons are similar for questions 13 - 17.

Elementary Geometry For College Students, 7e

7th Edition

ISBN:9781337614085

Author:Alexander, Daniel C.; Koeberlein, Geralyn M.

Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.

Chapter5: Similar Triangles

Section5.2: Similar Polygons

Problem 8E: Given that rectangle ABCE is similar to rectangle MNPR and that CDEPQR, what can you conclude...

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Similar questions

When the diagonals of rhombus MNPQ are drawn, how do the areas of the four resulting smaller triangles compare to each other and to the area of the given rhombus? Exercise 46
A calendar is determined by using each of the 12 faces of a regular dodecahedron for one month of the year. With each side of the regular pentagonal face measuring 4cm, the area of each face is approximately 27.5 cm2. a What is the total surface area of the calendar? b If the material used to construct the calendar costs 0.8 of a cent per square centimeter, what is the cost of the materials used in construction?
In Exercises 44 and 45, use the formula from Exercise 43. Similar triangles were used to find h and H. A container of yogurt has the shape of a frustum of a cone. With the lower base having diameter length 6 cm and the upper base having diameter length 8 cm, the volume of such a container 7.5 cm tall can be determined by using H=30 cm and h=22.5 cm. Find its volume. A frustum of a cone is the portion of the cone bounded between the circular base and a plane parallel to the base. With dimensions are indicated, show that the volume of the frustum of the cone is V=13R2H13rh2
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Given that rectangle ABCE is similar to rectangle MNPR and that CDEPQR, what can you conclude regarding pentagon ABCDE and pentagon MNPQR?