Unified Soil Classification SystemProblem Set No. 6Sieve No.DiameterPercent Finer(mm)2. The table below the laboratory results of thesieve analysis of a sample. Plot the grain sizecurve of the soil using your printed Grain SizeCurve. Determine the following:44.759082.3864102.0058200.8435a. Determine the nearest value of effective size.22b. Determine the coefficient of uniformity, Cc. Classify the soil according to USCS.400.42600.25151000.14910Showyour complete solution.2000.0754

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Answered: Unified Soil Classification System…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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The table shows the laboratory results of the sieve analysis of a sample. Plot the grain size curve of the soil. The soil has a liquid limit of 35% and plasticity index of 26%. SIEVE SIZE (mm) WEIGHT RETAINED 0.25 18.96 0.149 33.18 0.074 45.03 0.052 54.51 0.02 42.66 0.01 11.85 0.004 4.74 0.001 4.74 Pan 21.33 a.) Classify the soil using AASHTO method b.) Classify the soil using USCS method c.) Classify the soil using USDA method Please answer this asap. For upvote. Thank you in advance
Let us assume that a soil sample taken in the field is taken and it must be identified by the SUCS Method and AASHTO Method. Moisture content = 5.75% Limit liquid = 53.5 Plastic limit = 31.6 Granulometry Sieve % Pass No. 4 100 # 40 68 # 200 54.3 Do you select the best answer? a) Inorganic silt and sand, with low plasticity b) Inorganic clay with low plasticity c) Clay silt, traces of gravel, dark Brown
Find the mass of soil in grams required for the specimen preparation if; Height of the sampler = 3in Diameter of the sampler = 1.85in Density of the soil = 106.25 lb per cubic feet.
in a partially saturated soil e (void ratio) = 1.2; w = 30%; Ss = 2.66; calculate the γm(specific gravity of soil mass) and γd (dry specific weight of sample) of said soil. complete the diagram show in the image. I WILL RATE IT.
The laboratory compaction test of a certain type of soil gives a maximum dry density of 1.486 g/cc3 with an optimum moisture content of 12.5%. Determine the relative compaction of the soil using the following results of a filed unit weight determination test using sand cone method. Volume of soil excavated from the hole = 0.001337 m3 Weight of moist soil from the hole = 2220 g Weight of oven dried soil = 1890 g Select one: a. 97.25 b. 95.10 c. 90.34 d. 88.41
In order to calculate void ratio of a soil sample, which laboratory test(s) need(s) to be conducted? a. Liquid limit test b. Drying in oven c. Pumping well test d. Pycnometer test e. Ground Penetrating Radar tests f. Hydrometer analysis
In a soil test, it took 16.0 min for 1508 cm3 of water to flow through a sand sample. The cross-sectional area was 50.3 cm2 .The void ratio of the soil sample was 0.68. Determine 1.The velocity of water through the soil (apparent velocity) 2.Actual velocity/ Seepage velocity Kindly answer this question as soon as possible.
Following are the results of a field unit-weight determination test performed on the same soil by means of the sand cone method: -Calibrated dry unit weight of Ottawa sand = 15.4019 kn/m3 -Calibrated weight of Ottawa sand to fill the cone = 5.3496 N -Weightof jar + cone + sand (before use) = 74.451 N -Weightof jar + cone + sand (after use) = 46.886 N -Weight of moist soil from hole = 29.509 N -Moisture content of moist soil = 10.21% DETERMINE AND SHOW COMPLETE SOLUTION 1. Dry density of compaction in the field in kg/cu.m.
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/ . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/ ) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN and an optimum moisture content of 13%. (Ans: 97.07%)
A fully saturated clay sample has a mass of 1526 grams. After oven-drying, its mass was reduced to 1053 grams. The specific gravity of soil particles is 2.7. Calculate the natural water content of the sample in percent. Select one: a. 51.26 b. 44.92 c. 20.12 d. 36.17
2A sample of soil obtained from a borrow pit has a wet weight of 16 kg.The total volume occupied by the sample when in the ground was8490cm. A small portion of the sample is used to determine the watercontent. The wet sample weighs 150g. After drying, it weights 125g (a) What is the water content of the sample?(6) Determine the wet and the dry unit weights of the soil in the borrowpit.
2. Sand cone equipment is used to perform a field density test on a compacted earth fill. Sand is used in the cone and is known to have a bulk density of 15.74 kN/m3 . Soil sample dug from test hole, (wet weight) = 20.601 N Dry weight of soil sample = 17.926 N Weight of sand (sand cone) to fill test hole = 16.503 N Determine the in-place dry density of the tested soil (Ans: 17.57 kN/m3) Determine the water content (Ans: 15%) Compute the percentage of compaction of the tested soil if the laboratory moisture-density curve indicates a dry density of 18.10 kN/m3 and an optimum moisture content of 13%. (Ans: 97.07%)

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