uniform diameter d= 1.75 in.Segment (1) is an aluminumĘ₁ = 10000 ksiL₁ = 90 in.Segment (2) is a copperĘ₂ = 17000 ksi L₂ = 126 in.When Pis applied, a strain gage attached to copper segment (2) measures a normalstrain of &2 = 1700 uin./in. in the longitudinal direction.What is the elongation of segment (1)? Answer in inch rounded-off to 3 decimal placesL₁A(1)AluminumBL2(2)Copper

Answered: Image /qna-images/answer/40edc32b-2d07-4d07-8436-e2910ea8e044.jpg

uniform diameter d = 1.75 in. Segment (1) is an aluminum ₁ = 10000 ksi Segment (2) is a copper Ę₂ = 17000 ksi L₂ = 126 in. When Pis applied, a strain gage attached to copper segment (2) measures a normal strain of ₂ = 1700 μin./in. in the longitudinal direction. What is the elongation of segment (1)? Answer in inch rounded-off to 3 decimal places 4₁ = 90 in.

uniform diameter d = 1.75 in. Segment (1) is an aluminum ₁ = 10000 ksi Segment (2) is a copper Ę₂ = 17000 ksi L₂ = 126 in. When Pis applied, a strain gage attached to copper segment (2) measures a normal strain of ₂ = 1700 μin./in. in the longitudinal direction. What is the elongation of segment (1)? Answer in inch rounded-off to 3 decimal places 4₁ = 90 in.

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter1: Tension, Compression, And Shear

Section: Chapter Questions

Problem 1.6.7P: A wine of length L = 4 ft and diameter d = 0.125 in. is stretched by tensile forces P = 600 lb. The...

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