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uppose you reject the null hypothesis, use the LSD method to compare the difference in the meantime taken to find their first full-time job for Business and Computer Science graduates using 95% confidence interval.      a) [-2.036, 37.750]       b) [0.023, 26.370]       c) [2.036, 37.750]       d) [-0.023, 36.770]

uppose you reject the null hypothesis, use the LSD method to compare the difference in the meantime taken to find their first full-time job for Business and Computer Science graduates using 95% confidence interval.      a) [-2.036, 37.750]       b) [0.023, 26.370]       c) [2.036, 37.750]       d) [-0.023, 36.770]

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
Problem 8E
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1.Suppose you reject the null hypothesis, use the LSD method to compare the difference in the meantime taken to find their first full-time job for Business and Computer Science graduates using 95% confidence interval.

 

  

a) [-2.036, 37.750]

 

   

b) [0.023, 26.370]

 

   

c) [2.036, 37.750]

 

   

d) [-0.023, 36.770]

2

Suppose you must test the hypothesis at 5% level of significance whether the mean time taken to find their first full-time job for all May 2019 graduates in these fields is the same. What is your conclusion? a) Since F=2.092 is greater than"a F=4.21 we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are equal. F -4.21 b) Since F=2.092 is not greater than we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are not equal. F =4.21 c) Since F=2.092 is not greater than .we then reject the null hypothesis at 5% level of significance and conclude that all the means are equal. F =4.21 d) Since F=2.092 is not greater thana , we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are equal.
Transcribed Image Text:Suppose you must test the hypothesis at 5% level of significance whether the mean time taken to find their first full-time job for all May 2019 graduates in these fields is the same. What is your conclusion? a) Since F=2.092 is greater than"a F=4.21 we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are equal. F -4.21 b) Since F=2.092 is not greater than we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are not equal. F =4.21 c) Since F=2.092 is not greater than .we then reject the null hypothesis at 5% level of significance and conclude that all the means are equal. F =4.21 d) Since F=2.092 is not greater thana , we then fail reject the null hypothesis at 5% level of significance and conclude that all the means are equal.
A university employment office wants to compare the time taken by graduates with three different majors to find their first full-time job after graduation. The following table lists the time (in days) taken to find their first full-time job after graduation for a random sample of eight business majors, seven computer science majors, and six engineering majors who graduated in May 2019. SUMMARY Groups Count Sum Average Variance Business 1208 151 386 Computer Science 932 133.1429 253.4762 Law 898 149.6667 360.2667 ANOVA Source of Variation ss df MS P-value F crit Between Groups B 700.2381 0.152404 G Within Groups 6024.19 Total
Transcribed Image Text:A university employment office wants to compare the time taken by graduates with three different majors to find their first full-time job after graduation. The following table lists the time (in days) taken to find their first full-time job after graduation for a random sample of eight business majors, seven computer science majors, and six engineering majors who graduated in May 2019. SUMMARY Groups Count Sum Average Variance Business 1208 151 386 Computer Science 932 133.1429 253.4762 Law 898 149.6667 360.2667 ANOVA Source of Variation ss df MS P-value F crit Between Groups B 700.2381 0.152404 G Within Groups 6024.19 Total
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