Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) %3D = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.686 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 96E: What is the purpose of the Intermediate Value Theorem?
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Use appropriate Lagrange interpolating
polynomials of degrees three to
approximate
f(8.4) if f(8.1) = 16.94410, f(8.3) =
17.56492, f(8.6) = 18.50515, and f(8.7)
= 18.82091
O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686:
2.96077250
O P3(x)=0.002083333334x^3+0.1120833334x^2-4.6862
5.96077250
O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686:
4.96077250
O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68
2.96077250
Transcribed Image Text:Use appropriate Lagrange interpolating polynomials of degrees three to approximate f(8.4) if f(8.1) = 16.94410, f(8.3) = 17.56492, f(8.6) = 18.50515, and f(8.7) = 18.82091 O P3(x)=0.002083333334x^3+0.1120833334x^2+1.686: 2.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2-4.6862 5.96077250 O P3(x)=0.002083333334x^3+0.1120833334x^2+6.686: 4.96077250 O P3(x)=1.002083333334x^3+0.1120833334x^2+22.68 2.96077250
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