The phi-coefficient can be used to measure effect size for a Chi-Square for Independence if each of two nominal variables has of only 2 values (i.e., it is 2x2 design). A. True B. False
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The phi-coefficient can be used to measure effect size for a Chi-Square for Independence if each of two nominal variables has of only 2 values (i.e., it is 2x2 design).
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- A local restaurant claims that it gets 45 percent of its customers from Monday through Thursday, 20 percent on Friday, 20 percent on Saturday, and 15 percent on Sunday. How many degrees of freedom should be used to conduct a chi-square goodness-of-fit test of the claim?The contingency table shows the results of a random sample of former smokers by the number of times they tried to quit smoking before they were habit-free and gender. At α=0.10, can you conclude that the number of times they tried to quit before they were habit-free is related to gender? Perform the indicated chi-square independence test by completing parts (a) through (e) below.The closer the numerator of a t-test gets to zero, the more likely it is that there is no statistically significant difference between the two means we are testing. True False
- A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.Which of the following is a reason why fixed effect models can't estimate coefficients on variables that do not vary within unit? A, The errors will be homoscedastic. B, The de-meaned variables will not vary. C, We can estimate such a variable with fixed effects. D, Because no fixed effects exists in such a case.What is the z-score if mu = 89 , sigma=11.5, and x = 82 ?
- In a previous Paul, 44% of adults and children under the age of 18 reported that their family eat dinner together seven nights a week... use technology to find the P value. P value =_. (round to three decimal places as needed.) should one reject the null hypothesis? or should one not reject the null hypothesis?I'm having issue with E because I don't know the p-valueWhich of the following is NOT CORRECT? A) The past purchase frequency (freqi) affects the purchase probability positively – i.e., customers with high past purchase frequency are more likely to purchase our product in the next year than those with low past purchase frequency. B) In general, customers are likely to buy our product because the baseline parameter is negative. C) High-income customers are more likely to purchase our product in the next year than low- income customers because the coefficient corresponding to the income variable (incomei) is positive. D) Although the number of flyers (nmaili) positively affects the purchase probability, it is not guaranteed that sending flyers to customers as many as possible maximizes profits.
- A z-score of –1.6 has a corresponding Stanine score of:Kaitlyn measures the upload speed in megabits per second of her home broadband internet connection during peak hours and off-peak hours. The results are provided in the accompanying table. Peak Off-Peak 5.83 5.14 6.05 6.80 7.14 6.98 3.54 5.77 5.45 7.27 5.90 6.62 5.81 6.19 4.82 6.08 6.37 6.59 4.65 5.58 5.30 7.41 6.48 6.26 5.96 6.37 5.79 6.31 6.84 6.55 5.06 4.95 5.61 7.03 6.45 6.77 Examine the results of Kaitlyn's test to determine the statements that compare the medians and interquartile ranges of the data sets to each other in terms of this situation. Select the two correct answers. The median upload speed during peak hours is 5.905 megabits per second, which is less than the median upload speed during off-peak hours, 7.005 megabits per second. The upload speeds during peak hours are slower on average compared to off-peak times. The median upload speed during peak hours is 6.37 megabits per second, which is greater than the median upload speed during…An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberry drink and another sample filled with cola. Beverage Sample Size Sample Mean Sample SD Strawberry Drink 10 535 24 Cola 10 559 15 Does the data suggest that the extra carbonation of cola results in a higher average compression strength? Base your answer on a P-value. (Use ? = 0.05.) State the relevant hypotheses. (Use ?1 for the strawberry drink and ?2 for the cola.) H0: ?1 − ?2 = 0Ha: ?1 − ?2 ≥ 0H0: ?1 − ?2 = 0Ha: ?1 − ?2 ≠ 0 H0: ?1 − ?2 = 0Ha: ?1 − ?2 < 0H0: ?1 − ?2 = 0Ha: ?1 − ?2 > 0 Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. Reject H0. The data suggests that cola has a higher average compression strength than the strawberry drink.Reject H0. The…