Use bond energies to calculate the H for the following reaction: N,H4 + H2O ---> NH,OH + NH3 N--H = 391 kJ/mol N--N = 163 kJ/mol N--N = 418 kJ/mol N--N = 941 %3D kJ/mol H--H = 432 kJ/mol O--H = 467 kJ/mol O--O = 146 kJ/mol O--O = 495 kJ/mol N--O = 201 kJ/mol N--O = 415 %3D kJ/mol

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter9: Chemical Bonds
Section: Chapter Questions
Problem 9.94QE
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Use bond energies to calculate the H for
the following reaction:
N,H4 + H2O ---> NH,OH + NH3
N--H = 391 kJ/mol
N--N = 163
kJ/mol
N--N = 418
%3D
kJ/mol
N--N = 941
kJ/mol
H--H = 432
%3D
kJ/mol
O--H = 467
kJ/mol
O--O = 146
kJ/mol
O--O = 495
%3D
kJ/mol
N--O = 201
%3D
kJ/mol
N--O = 415
kJ/mol
Transcribed Image Text:Use bond energies to calculate the H for the following reaction: N,H4 + H2O ---> NH,OH + NH3 N--H = 391 kJ/mol N--N = 163 kJ/mol N--N = 418 %3D kJ/mol N--N = 941 kJ/mol H--H = 432 %3D kJ/mol O--H = 467 kJ/mol O--O = 146 kJ/mol O--O = 495 %3D kJ/mol N--O = 201 %3D kJ/mol N--O = 415 kJ/mol
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