use initial conditions u (0, t) = 0 and u (T, t) = 0 u (0, t) = (c1 + c2) (c4 + c3t) = 0 » (c1 + c2) (c4 + c3t) = 0 %3D u (T, t) = (c1 + cze) (c4 + c3t) = 0 > (ci + cze-*) (c4 + c3t) = 0 this condition is only possible if c1 = c2 = C3 = c4 = 0

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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I'm having trouble understanding why these two conditions imply that c1=c2=c3=c4=0.  Wouldn't both equations still hold if c3=c4=0 only?  Or just c1 and c2?  Why do all four of them have to be 0?

use initial conditions
и (0, t) — 0 and u (п, t) — 0
u (0, t) = (c1 + c2) (c4 + c3t) = 0
→ (c1 + c2) (c4 + czt) = 0
u (T, t)
(ci + cze) (c4 + c3t) = 0
C2e
(ci + cze-*) (c4 + c3t) = 0
this condition is only possible if c1 = c2 = C3 = C4 = 0
Transcribed Image Text:use initial conditions и (0, t) — 0 and u (п, t) — 0 u (0, t) = (c1 + c2) (c4 + c3t) = 0 → (c1 + c2) (c4 + czt) = 0 u (T, t) (ci + cze) (c4 + c3t) = 0 C2e (ci + cze-*) (c4 + c3t) = 0 this condition is only possible if c1 = c2 = C3 = C4 = 0
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