Use linear approximation, i.e. the tangent line, to approximate 27.1 as follows: Let f(x)=x. The equation of the tangent line to f(x) at x = 27 can be written in the form y = mx + b where m is: and where b is: Using this, we find our approximation for 27.1 is
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- Solve the following exercises based on Principles 15-17, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated. Points E, G, and F are tangent points. a. If 1 = 109", find 2. b. If 1 = 11845', find 2.Solve the following exercises based on Principles 15-17, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated. AB and CB are tangents. a. If y = 137.20 mm and ABC = 67.0, find (1) 1 and (2) x. If y = 207.70 mm and 1 = 33.8, find (1) ABC and (2) y.Solve the following exercises based on Principles 15-17, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated. Point A is a tangent point of the V-groove cut and pin shown. All dimensions are in inches. a. If y = 1.400", find x. b. If y = 1.800", find x.
- Solve the following exercises based on Principles 11-14, although an exercise may require the application of two or more of any of the principles. Round the answers to 3 decimal places where necessary unless otherwise stated. a. If radius x = 7.500" and y = 4.500", find PM. b. If radius x = 8.000" and y = 4.800", find PM.Consider the following function. square root of x, (1, 1) (a) Find an equation of the tangent line to the graph of f at the given point.Use linear approximation, i.e. the tangent line, to approximate 1.954 as follows:Let f(x)=x4 . The equation of the tangent line to f(x) at x=2 can be written in the form y=mx+bwhere m is:and where b is:Using this, we find our approximation for 1.954 is:
- Use linear approximation, i.e. the tangent line, to approximate 2.7^6 as follows: Let f(x)=x^6. The equation of the tangent line to f(x) at x=3 can be written in the form y=mx+b where m=? b=? Using this, we find our approximation for 2.7^6 is ___?Use linear approximation, i.e. the tangent line, to approximate 1.8 to the 4th powet as follows: Let f(x)=x to the 4th power . The equation of the tangent line to f(x) at x=2 can be written in the form y=mx+b where m is: and where b is: Using this, we find our approximation for 1.8 to the 4th power isUse linear approximation, i.e. the tangent line, to approximate 4.9^7 as follows:Let f(x)=x^7. The equation of the tangent line to f(x) at x=5 can be written in the form y=mx+bwhere m is: and where b is: Using this, we find our approximation for 4.9^7 is
- Given that f(2)=−3 and f′(2)=6, find an equation for the tangent line to the graph of y=f(x) at x=2.Find the two possible values of a so that the tangent lines to f(x) = x3+2x2 and to g(x) = 8x-3x2 at the points (a, f(a)) and (a, g(a)), respectively, are parallel.Use linear approximation, i.e. the tangent line, to approximate ^3√64.2 as follows: Let f(x) = ^3√x. The equation of the tangent line to f(x) at x=64 can be written in the form y=mx+b. Where m is =? And where b is = ? Using this, we find our approximation for ^3√64.2 is =?