Use linear approximation, i.e. the tangent line, to approximate V125.2 as follows: Let f(x) = Va. The equation of the tangent line to f(x) at x = 125 can be written in the form y = mx + 6 where m is: and where b is: Using this, we find our approximation for V125.2 is

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Q: Write the equation of the tangent line in Cartesian coordinates for the given parameter t. x = eVE y…

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