Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.10 years and a standard deviation of 2.00 years. Random samples of size 15are drawn from the population and the mean of each sample is determined. Round the answers to the nearest hundredth.A. 5.10 years, 0.52 yearsOB. 5.10 years, 0.13 yearsOC. 1.32 years, 2.00 yearsD. 1.32 years, 0.52 years 7 of 10 (0 comFind the area under the standard normal curve to the right of z = 1.O A. 0.5398B. 0.8413O C. 0.1587O D. 0.1397Click to select your answer.

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Description: Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.

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Use the Central Limit Theorem to find the mean and standard error of the mean of the indicated sampling distribution.
The amounts of time employees of a telecommunications company have worked for the company are normally distributed with a mean of 5.10 years and a standard deviation of 2.00 years. Random samples of size 15
are drawn from the population and the mean of each sample is determined. Round the answers to the nearest hundredth.
A. 5.10 years, 0.52 years
OB. 5.10 years, 0.13 years
OC. 1.32 years, 2.00 years
D. 1.32 years, 0.52 years

7 of 10 (0 com
Find the area under the standard normal curve to the right of z = 1.
O A. 0.5398
B. 0.8413
O C. 0.1587
O D. 0.1397
Click to select your answer.

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Since, you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.

From the provided information,

Mean (µ) = 5.10

Standard deviation (σ) = 2.00

X~N (5.10, 2.00)

Here X be a random variable which represents the amounts of time employees of a telecommunications company.

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