Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule. Al203 (s) + 6 NaOH (4 + 6 HF (g)→ 2 NasAIF6 (s) + 6 H2O (g) wwww 101.96 40.00 20.01 209.95 18.02 Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm wwn pressure in the presence of excess NaOH? Part b), How much energy is released from the reaction of 56.0 g of HF? Assume that H for the reaction is -345 kJ.

Chemistry: Principles and Practice
3rd Edition
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Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
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Chapter6: The Gaseous State
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Use the equation that follows for parts (a) and (b) below. Molecular masses are under each
salt/molecule.
AlżO3 (s) + 6 NaOH () + 6 HF (g) →
2 Na3AIF6 (s) + 6 H2O (g)
101.96 40.00 20.01 209.95 18.02
Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm
pressure in the presence of excess NaOH?
Part b) How much energy is released from the reaction of 56.0g of HF? Assume that BH for the
reaction is -345 kJ.
Transcribed Image Text:Use the equation that follows for parts (a) and (b) below. Molecular masses are under each salt/molecule. AlżO3 (s) + 6 NaOH () + 6 HF (g) → 2 Na3AIF6 (s) + 6 H2O (g) 101.96 40.00 20.01 209.95 18.02 Part a) How many grams of aluminum oxide are needed to react with 3.5 L of HF at 305 K, 4.2 atm pressure in the presence of excess NaOH? Part b) How much energy is released from the reaction of 56.0g of HF? Assume that BH for the reaction is -345 kJ.
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