Use the following thermochemical equations as needed to find the heat of formation of diamond. C(diamond)+O2(g)⟶CO2(g)△H∘=−395.4kJC(diamond)+O2(g)⟶CO2(g)△H∘=−395.4kJ 2CO2(g)⟶2CO(g)+O2(g)△H∘=566.0kJ2CO2(g)⟶2CO(g)+O2(g)△H∘=566.0kJ C(graphite)+O2(g)⟶CO2(g)△H∘=−393.5kJC(graphite)+O2(g)⟶CO2(g)△H∘=−393.5kJ 2CO(g)⟶C(graphite)+CO2(g)△H∘=−172.5kJ

General Chemistry - Standalone book (MindTap Course List)
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.146QP: Given the following (hypothetical) thermochemical equations:...
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1.  Use the following thermochemical equations as needed to find the heat of formation of diamond.

C(diamond)+O2(g)⟶CO2(g)△H∘=−395.4kJC(diamond)+O2(g)⟶CO2(g)△H∘=−395.4kJ

2CO2(g)⟶2CO(g)+O2(g)△H∘=566.0kJ2CO2(g)⟶2CO(g)+O2(g)△H∘=566.0kJ

C(graphite)+O2(g)⟶CO2(g)△H∘=−393.5kJC(graphite)+O2(g)⟶CO2(g)△H∘=−393.5kJ

2CO(g)⟶C(graphite)+CO2(g)△H∘=−172.5kJ

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