Use the Laplace transform to solve the given initial-value problem. 0, 0 ≤ t < T 1, π ≤ t < 2π t≥ 2π 0, y" + y = f(t), y(0) = 0, y'(0) = 1, where f(t) = y(t) = sin(t) + 1 + cos(t) )u(t - n) + (1 - cos (t) × )u(t - 2n

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