Use the maximum and minimum principle to deduce that the solution of: Ut = Ugr) 0 < x < 3, t > 0 subject to the initial and boundary conditions u(x, 0) = 6 sin + 2 sin(2æ), 0 < æ < 3, 3 u(0, t) = u(3, t) = 0, satisfies 0 < u(x, t) < 4/2.

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Use the maximum and minimum principle to deduce that the solution of:
Ut = Ugx)
0 < x < 3, t > 0
subject to the initial and boundary conditions
u(x, 0) = 6 sin
+ 2 sin(2x), 0 < x < 3,
3
u(0, t) = u(3, t) = 0,
satisfies 0 < u(x, t) < 4/2.
Transcribed Image Text:Use the maximum and minimum principle to deduce that the solution of: Ut = Ugx) 0 < x < 3, t > 0 subject to the initial and boundary conditions u(x, 0) = 6 sin + 2 sin(2x), 0 < x < 3, 3 u(0, t) = u(3, t) = 0, satisfies 0 < u(x, t) < 4/2.
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