Question
Asked Jun 6, 2019
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Use the method of integrating factors to solve the given initial value problem.

  • y'+3x2y=sin(x)e-x^3, y(0)=1
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Expert Answer

Step 1

The given equation is

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y3x2ysinxe ,y(0)1

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Step 2

Note that, the given equation first order linear differential equation which is in the form of

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yp(x)yq(x) where p(x)3x and q(x)= sin(x)e

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Step 3

Compute the integrating f...

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pix 3x3 pix 3 = e pc That is, the integrating factor is u(x)= e"

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